获取两个时间的时间差（以分钟为例）

电玩女神 2024-03-31 15:20 34阅读 0赞

测试：

public static void main(String[] args) {
            Date date = new Date();
            SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
            String endTime = simpleDateFormat.format(date);
            try{
                long i=getTimeDifference("2022-12-05 12:00:00",endTime);
                if(i<10) {
                    System.out.println("维修时间为" + i + "分钟！,需超过10分钟！");
                }else {
                    System.out.println("维修完成");
                }
            }catch(Exception e) {
                e.printStackTrace();
            }

工具类：

public static long getTimeDifference(String oldTime,String newTime) throws ParseException {
    
            SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
            long NTime =df.parse(newTime).getTime();
            //从对象中拿到时间
            long OTime = df.parse(oldTime).getTime();
            long diff=(NTime-OTime)/1000/60;
            return diff;
        }

结果

![4a5b2f00c0b44b64a363ae85dfccd753.png][]

![bf2046407c3a460cac61062811aa89c1.png][]

public static void main(String[] args) throws ParseException {
        //十位数时间戳
        long start = 1611298952;
        long end = 1611299007;
        long diffSeconds = end - start;
        Double minute = new BigDecimal((float) diffSeconds / 60).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
        Double hour = new BigDecimal((float) diffSeconds / (60 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
        //时间戳为13位时
        //Double minute = new BigDecimal((float) diffSeconds / (1000 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
        //Double hour = new BigDecimal((float) diffSeconds / (1000 * 60 * 60)).setScale(2, BigDecimal.ROUND_HALF_UP).doubleValue();
        System.out.println(minute);   //打印结果：0.92
        System.out.println(hour);   //打印结果：0.02
    }

[4a5b2f00c0b44b64a363ae85dfccd753.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/03/31/5b39e0b05a6e4f7d91d85ac03aa6d42f.png
[bf2046407c3a460cac61062811aa89c1.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/03/31/e1be37cba5c54fe0aae26d28a4957c1c.png