android 使用XmlSerializer生成xml文件方法

朱雀 2021-06-24 13:59 539阅读 0赞

### package com.android.antking.xml;       import java.io.OutputStream;   import java.util.List;       import org.xmlpull.v1.XmlSerializer;       import android.util.Xml;           /\*\*采用pull 生成xml文件    \*     \* @author antkingwei    \*    \*/   public class PullBuildXMLService \{           public void buildXML(List<Person> persons,OutputStream outputStream)throws Exception\{           XmlSerializer serializer = Xml.newSerializer();           serializer.setOutput(outputStream,"utf-8");           serializer.startDocument("utf-8", true);           serializer.startTag(null, "perisons");           for(Person person:persons)\{               serializer.startTag(null, "perison");               serializer.attribute(null, "id",String.valueOf(person.id));                               serializer.startTag(null, "name");               serializer.text(person.name);               serializer.endTag(null, "name");                               serializer.startTag(null, "age");               serializer.text(String.valueOf(person.age));               serializer.endTag(null, "age");                   serializer.endTag(null, "perison");           \}           serializer.endTag(null, "perisons");           serializer.endDocument();           outputStream.close();       \}   \}    ###

2、业务bean

public class Person \{  
     public int id;  
     public String name;  
     public int age;  
    \}

3、调用：

public void writeFile() throws Throwable\{  
      List<Person> list = new ArrayList<Person>();  
     for(int i =0;i<10;i++)\{  
         Person person = new Person();  
         person.id = 1;  
         person.name = "ant";  
         person.age = 12;  
         list.add(person);  
     \}  
      File file = new File(MainActivity.this.getFilesDir(),"person.xml");  
      FileOutputStream outputStream  = new FileOutputStream(file);  
      PullBuildXMLService service = new PullBuildXMLService();  
      service.buildXML(list, outputStream);  
         
   \}