sed use case: Filter without editing
if we want to filter with sed pattern and just print the filtered lines without any further editing , we can do it like this
ls -a1 ~ | sed -ne "/^\./p"
This command will print all dir entries that starts with “.”
ls -a1 ~ | sed -ne "/^\./p" | sed -ne "/bash/p"
I want to find meta files related to bash, so I got the result:
.bash_history.bash_logout.bashrc
we can view each file content by
ls -a1 ~ | sed -ne "/^\./p" | sed -ne "/bash/p" | xargs -n 1 less
delete file and directories except “term.sh” and “test.cpp”
ls | sed -e "/^term.sh$/d" | sed -e "/^test.cpp$/d" | xargs -n 1 rm -rf
show contents of all status file in current directory tree
find . -iname status | xargs -n 1 less
转载于
//www.cnblogs.com/long123king/p/3754581.html
墨蓝
Bertha 。
朱雀
ゞ 浴缸里的玫瑰
迷南。
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