多进程爬取

柔情只为你懂 2022-01-12 15:59 208阅读 0赞

import requests
 from lxml import etree
 import re
 import time
 from multiprocessing import Pool #导入multiprocessing库的Pool模块
 
 headers = {'user-agent':'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/69.0.3497.92 Safari/537.36'}
 
 def get_info(url):
 html = requests.get(url,headers = headers)
 selector = etree.HTML(html.text)
 names = selector.xpath('//*[@class="article block untagged mb15 typs_hot"]/div[1]/a[2]/h2/text()')
 centents = re.findall('<div class="content">.*?(.*?)',html.text,re.S) #第一个正则是为了匹配换行符
 laughs = re.findall('(\d+)',html.text,re.S)
 comments = re.findall('(\d+) 评论',html.text,re.S)
 for name,centent,laugh,comment in zip(names,centents,laughs,comments):
 info = {
 'name':name,
 'centent':centents,
 'laugh':laughs,
 'comment':comments
 }
 return (info)
 
 if __name__ == '__main__':
 urls = ["https://www.qiushibaike.com/text/page/{}/".format(num)for num in range(0,14)]
 start_1 = time.time()
 for url in urls:
 get_info(url)
 end_1 = time.time()
 print('串行爬取花费时间：' + str(end_1 - start_1))
 
 start_2 = time.time()
 pool = Pool(processes=2) #创建进程池，processes为设置的进程个数
 pool.map(get_info,urls) #利用map()函数运行进程，参数fuc为运行的函数，iterable为迭代参数
 end_2 = time.time()
 print('2个进程：' + str(end_2 - start_2))
 
 start_3 = time.time()
 pool = Pool(processes=4) # 创建进程池，processes为设置的进程个数
 pool.map(get_info, urls) # 利用map()函数运行进程，参数fuc为运行的函数，iterable为迭代参数
 end_3 = time.time()
 print('4个进程：' + str(end_3 - start_3))

输出：

D:\Python\venv\Scripts\python.exe D:/Python/venv/test12.py
    串行爬取花费时间：5.043288469314575
    2个进程：3.351191759109497
    4个进程：2.882164716720581
    
    Process finished with exit code 0

转载于:https://blog.51cto.com/12884584/2358703