#20 Valid Parentheses——Top 100 Liked Questions
Given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
An input string is valid if:
- Open brackets must be closed by the same type of brackets.
- Open brackets must be closed in the correct order.
Note that an empty string is also considered valid.
Example 1:
Input: "()"
Output: true
Example 2:
Input: "()[]{}"
Output: true
Example 3:
Input: "(]"
Output: false
Example 4:
Input: "([)]"
Output: false
Example 5:
Input: "{[]}"
Output: true
“””
第一次:使用栈stack,如果遇到左括号,压入栈中,如果遇到右括号:1)如果stack为空,没有与左括号匹配的右括号,返回false;2)stack不为空,弹出左括号,判断是否与当前右括号匹配,如果匹配,匹遍历下一个括号,不匹配,返回false;3)遍历完成后,看stack中是否有多余的左括号没找到匹配对象,有则返回false
“””
class Solution(object):
def isValid(self, s):
"""
:type s: str
:rtype: bool
"""
stack = []
for bra in s:
if bra in ['(', '[', '{']:
stack.append(bra)
else:
if len(stack) == 0:
return False
else:
check = stack.pop()
if (check == '(' and bra == ')') or (check == '[' and bra == ']') or (check == '{' and bra == '}'):
continue
else:
return False
return len(stack) == 0
“””
Runtime: 20 ms, faster than 93.77% of Python online submissions for Valid Parentheses.
Memory Usage: 11.9 MB, less than 5.20% of Python online submissions for Valid Parentheses.
“””
还没有评论,来说两句吧...