Python 用datetime模块时间计算精确的天数差

清疚 2022-02-27 05:51 348阅读 0赞

from datetime import datetime
    local_time = datetime.now() #获取系统时间 local_time = datetime.datetime.now()
    print type(local_time),"local_time= ",local_time
    # 字符串转日期
    data_time = datetime.strptime('2019-03-20 15:25:30', '%Y-%m-%d %H:%M:%S')
    print type(data_time), data_time
    Expenses_days = local_time–data_time
    print Expenses_days

Python 2.7.14 (v2.7.14:84471935ed, Sep 16 2017, 20:19:30) [MSC v.1500 32 bit (Intel)] on win32
    Type "help", "copyright", "credits" or "license" for more information.
    >>> from datetime import datetime
    >>> local_time = datetime.now() #获取系统时间 local_time = datetime.datetime.now()
    >>> print type(local_time),"local_time= ",local_time
    <type 'datetime.datetime'> local_time=  2019-03-26 22:23:20.742000
    >>> # 字符串转日期
    ... data_time = datetime.strptime('2019-03-20 15:25:30', '%Y-%m-%d %H:%M:%S')
    >>> print type(data_time), data_time
    <type 'datetime.datetime'> 2019-03-20 15:25:30
    >>> Expenses_days = local_time-data_time
    >>> print Expenses_days
    6 days, 6:57:50.742000
    >>> print Expenses_days.days
    6
    >>> print Expenses_days.seconds
    25070
    >>> print Expenses_days.microseconds
    742000
    >>> print Expenses_days.days+ Expenses_days.seconds/(24.0*60.0*60.0)
    6.29016203704

print Expenses\_days 显示  6 days, 6:57:50.742000

print Expenses\_days.days  显示  6 天

print Expenses\_days.seconds 显示  25070 秒 （25070/(60\*60)） = 6.93小时，即6:57:50

print Expenses\_days.microseconds 显示 742000 微妙

print Expenses\_days.days+ Expenses\_days.seconds/(24.0\*60.0\*60.0)  显示  6.29016203704天

所以当要计算2个精确的天数时间差的时候，需要用.days先算出整天，后用.seconds 算出秒数，再除以24\*60\*60（一天24小时，一小时60分，一分60秒），2者相加为精确的天数时间差。