水池进水与出水问题 -- 线程 java

阳光穿透心脏的1/2处 2022-03-20 11:26 249阅读 0赞

## 水池进水与出水问题 – 线程 java ##

package com.xzy;
    /**
     *    有一个水池，水池的容量是固定 的500L,一边为进水口,一边为出水口.
     *    要求,进水与放水不能同时进行. 水池一旦满了不能继续注水,一旦放空了,不可以继续放水. 
     *    进水的速度5L/s , 放水的速度2L/s  
     * @author 娟娟
     *
     */
    
    //水池
    class Pool{
    	int capacity = 0;//水池的容量
    }
    
    //进水口
    class inWater extends Thread{
    	Pool p;
    	
    	public inWater(Pool p) {
    		this.p = p;
    	}
    	
    	@Override
    	public void run() {
    		while(true) {
    			synchronized (p) {
    				if((p.capacity + 5) <= 50) {
    					System.out.println("进水中，水池的容量为：" + (p.capacity + 5));
    					p.capacity += 5; 
    					try {
    						Thread.sleep(2000);
    					} catch (InterruptedException e) {
    						e.printStackTrace();
    					}
    					p.notify();
    				}else {
    					System.out.println("水池水满了...");
    					try {
    						p.wait();
    					} catch (InterruptedException e) {
    						e.printStackTrace();
    					}
    				}
    			}
    		}
    	}
    }
    
    //出水口
    class outWater extends Thread{
    	Pool p;
    	
    	public outWater(Pool p) {
    		this.p = p;
    	}
    	
    	@Override
    	public void run() {
    		while(true) {
    			synchronized (p) {
    				if((p.capacity - 2) >= 0) {
    					System.out.println("出水中，水池的容量为" + (p.capacity - 2));
    					p.capacity -= 2;
    					try {
    						Thread.sleep(1000);
    					} catch (InterruptedException e) {
    						e.printStackTrace();
    					}
    					p.notify();
    				}else {
    					System.out.println("水池没水了...");
    					try {
    						p.wait();
    					} catch (InterruptedException e) {
    						e.printStackTrace();
    					}
    				}
    			}
    		}
    	}
    }
    
    public class Main {
    	public static void main(String[] args) {
    		Pool p = new Pool();
    		inWater iw = new inWater(p);
    		outWater ow = new outWater(p);
    		iw.start();
    		ow.start();
    	}
    }