Invert a binary tree.

4
   /   \
  2     7
 / \   / \
1   3 6   9

4
   /   \
  7     2
 / \   / \
9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.

这道题让我们翻转二叉树，是树的基本操作之一，不算难题。最下面那句话实在有些木有节操啊，不知道是Google说给谁的。反正这道题确实难度不大，可以用递归和非递归两种方法来解。先来看递归的方法，写法非常简洁，五行代码搞定，交换当前左右节点，并直接调用递归即可，代码如下：

public class liubobo_7_2 {
/// 226. Invert Binary Tree
/// https://leetcode.com/problems/invert-binary-tree/description/
/// 时间复杂度: O(n), n为树中节点个数
/// 空间复杂度: O(h), h为树的高度
    // Definition for a binary tree node.
    public class TreeNode {
        int val;
        TreeNode left;
        TreeNode right;
        TreeNode(int x) { val = x; }
    }
    public TreeNode invertTree(TreeNode root) {
        if(root == null)
            return null;
        TreeNode left = invertTree(root.left);
        TreeNode right = invertTree(root.right);
        root.left = right;
        root.right = left;
        return root;
    }
}