GPS坐标转百度坐标

偏执的太偏执、 2022-05-01 13:18 411阅读 0赞

转自：[https://blog.csdn.net/zkcharge/article/details/51727416][https_blog.csdn.net_zkcharge_article_details_51727416]

static double pi = 3.14159265358979324;

static double a = 6378245.0;  
static double ee = 0.00669342162296594323;  
public final static double x\_pi = 3.14159265358979324 \* 3000.0 / 180.0;  
  
public static double\[\] wgs2bd(double lat, double lon) \{  
       double\[\] wgs2gcj = wgs2gcj(lat, lon);  
       double\[\] gcj2bd = gcj2bd(wgs2gcj\[0\], wgs2gcj\[1\]);  
       return gcj2bd;  
\}  
  
public static double\[\] gcj2bd(double lat, double lon) \{  
       double x = lon, y = lat;  
       double z = Math.sqrt(x \* x + y \* y) + 0.00002 \* Math.sin(y \* x\_pi);  
       double theta = Math.atan2(y, x) + 0.000003 \* Math.cos(x \* x\_pi);  
       double bd\_lon = z \* Math.cos(theta) + 0.0065;  
       double bd\_lat = z \* Math.sin(theta) + 0.006;  
       return new double\[\] \{ bd\_lat, bd\_lon \};  
\}  
  
public static double\[\] bd2gcj(double lat, double lon) \{  
       double x = lon - 0.0065, y = lat - 0.006;  
       double z = Math.sqrt(x \* x + y \* y) - 0.00002 \* Math.sin(y \* x\_pi);  
       double theta = Math.atan2(y, x) - 0.000003 \* Math.cos(x \* x\_pi);  
       double gg\_lon = z \* Math.cos(theta);  
       double gg\_lat = z \* Math.sin(theta);  
       return new double\[\] \{ gg\_lat, gg\_lon \};  
\}  
  
public static double\[\] wgs2gcj(double lat, double lon) \{  
       double dLat = transformLat(lon - 105.0, lat - 35.0);  
       double dLon = transformLon(lon - 105.0, lat - 35.0);  
       double radLat = lat / 180.0 \* pi;  
       double magic = Math.sin(radLat);  
       magic = 1 - ee \* magic \* magic;  
       double sqrtMagic = Math.sqrt(magic);  
       dLat = (dLat \* 180.0) / ((a \* (1 - ee)) / (magic \* sqrtMagic) \* pi);  
       dLon = (dLon \* 180.0) / (a / sqrtMagic \* Math.cos(radLat) \* pi);  
       double mgLat = lat + dLat;  
       double mgLon = lon + dLon;  
       double\[\] loc = \{ mgLat, mgLon \};  
       return loc;  
\}  
  
private static double transformLat(double lat, double lon) \{  
       double ret = -100.0 + 2.0 \* lat + 3.0 \* lon + 0.2 \* lon \* lon + 0.1 \* lat \* lon + 0.2 \* Math.sqrt(Math.abs(lat));  
       ret += (20.0 \* Math.sin(6.0 \* lat \* pi) + 20.0 \* Math.sin(2.0 \* lat \* pi)) \* 2.0 / 3.0;  
       ret += (20.0 \* Math.sin(lon \* pi) + 40.0 \* Math.sin(lon / 3.0 \* pi)) \* 2.0 / 3.0;  
       ret += (160.0 \* Math.sin(lon / 12.0 \* pi) + 320 \* Math.sin(lon \* pi  / 30.0)) \* 2.0 / 3.0;  
       return ret;  
\}  
  
private static double transformLon(double lat, double lon) \{  
       double ret = 300.0 + lat + 2.0 \* lon + 0.1 \* lat \* lat + 0.1 \* lat \* lon + 0.1 \* Math.sqrt(Math.abs(lat));  
       ret += (20.0 \* Math.sin(6.0 \* lat \* pi) + 20.0 \* Math.sin(2.0 \* lat \* pi)) \* 2.0 / 3.0;  
       ret += (20.0 \* Math.sin(lat \* pi) + 40.0 \* Math.sin(lat / 3.0 \* pi)) \* 2.0 / 3.0;  
       ret += (150.0 \* Math.sin(lat / 12.0 \* pi) + 300.0 \* Math.sin(lat / 30.0 \* pi)) \* 2.0 / 3.0;  
       return ret;

我提供的是JAVA代码，简单注释一下：  
pi: 圆周率。  
a: 卫星椭球坐标投影到平面地图坐标系的投影因子。  
ee: 椭球的偏心率。  
x\_pi: 圆周率转换量。  
transformLat(lat, lon): 转换方法，比较复杂，不必深究了。输入：横纵坐标，输出：转换后的横坐标。  
transformLon(lat, lon): 转换方法，同样复杂，自行脑补吧。输入：横纵坐标，输出：转换后的纵坐标。  
wgs2gcj(lat, lon): WGS坐标转换为GCJ坐标。  
gcj2bd(lat, lon): GCJ坐标转换为百度坐标。

效果图：

![Center][]

[https_blog.csdn.net_zkcharge_article_details_51727416]: https://blog.csdn.net/zkcharge/article/details/51727416
[Center]: /images/20220119/cb80b7047e1649a0ab665558342ce9ac.png