c语言-10进制字符串转16进制字符串

小咪咪 2022-05-08 00:54 277阅读 0赞

**代码1-动态分配：**

#include <stdio.h>
    #include <string.h>
    #include <malloc.h>
    char *DecToHex(char *pHex,char *pDec,int Declen)
    {
    	int       i,Hexlen = Declen *2;
    	char        hex[] = "0123456789";
    	pHex = (char *)malloc(sizeof(char)*Hexlen);
    	for (i = 0; i < Declen; i++)
    	{
    		*pHex++ = hex[*pDec>>4];
    		*pHex++ = hex[*pDec++ & 0x0F];
    	}
    	*pHex = '\0';
    	return pHex -Hexlen;
    }
    int main()
    {
    	char Dec[] = "01234";
    	char *pHex = NULL;
    	printf("-------------10进制字符串----------\n");
    	printf("%s\n",Dec);
    	printf("-------------16进制字符串----------\n");
    	printf("%s\n", DecToHex(pHex,Dec,strlen(Dec)));
    	printf("\n\n\n");
    }

代码2-非动态分配:

#include <stdio.h>
    #include <string.h>
    #include <malloc.h>
    char *DecToHex(char *pHex,char *pDec,int Declen)
    {
    	int       i,Hexlen = Declen *2;
    	char        hex[] = "0123456789";
    	for (i = 0; i < Declen; i++)
    	{
    		*pHex++ = hex[*pDec>>4];
    		*pHex++ = hex[*pDec++ & 0x0F];
    	}
    	*pHex = '\0';
    	return pHex -Hexlen;
    }
    int main()
    {
    	char Dec[] = "01234";
    	char Hex[11];
    	printf("-------------10进制字符串----------\n");
    	printf("%s\n",Dec);
    	printf("-------------16进制字符串----------\n");
    	printf("%s\n", DecToHex(Hex,Dec,strlen(Dec)));
    	printf("\n\n\n");
    }

当然，如果你想完成Ascii码到Hex的转换，只需要将hex\[\]="0123456789"改成，hex\[\]="0123456789ABCDEF"。这也是为什么上面没做保护性判断，因为这个函数主要就是完成Ascii到Hex的转换，只是在这里是一种更特殊的情况。

**运行结果:**

![70][]

[70]: /images/20220508/a0444279a5b44dee8c7f2e3fce9c4fc4.png