java 正则匹配所有 {}，并取出所有符合的字符串。

雨点打透心脏的1/2处 2022-05-08 06:03 622阅读 0赞

\*\*\*测试demo        git仓库： [https://github.com/alwaysInRoad/test-regex-demo][https_github.com_alwaysInRoad_test-regex-demo]

csdn下载地址： [https://download.csdn.net/download/weixin\_40841731/10708981][https_download.csdn.net_download_weixin_40841731_10708981]

说明：

开发过程中实际项目所用到的场景：对自定义的 sql 内定义的规范参数进行替换。如一句sql中包含 \#\{id\},我们就把\#\{id\}替换成生成的id。

主要代码：将字符串中的所有  \#E\{xxxx\} 替换掉

public static void main(String[] args){
    	String sqlFragment = "insert into t_role(role_id,role_name,"
    	+ "role_level,org_id,role_type,role_status,add_user_id,"
    	+ "add_time,upd_user_id,upd_time) values(#{id},"
    	+ "${role_name},${role_level},${org_id},${role_type},"
    	+ "${role_status},"
    	+ "#E{accId},#{dateInt},#{accId},#E{dateInt})";
    	Pattern pattern = Pattern.compile("#E\\{[\\w]*\\}");
    	Matcher matcher = pattern.matcher(sqlFragment);
    	//循环，字符串中有多少个符合的，就循环多少次
    	while(matcher.find()){
    		//每一个符合正则的字符串
    		String e = matcher.group();
    		//截取出括号中的内容
    		String substring = e.substring(3, e.length()-1);
    		//字符串截取
    		CharSequence subSequence = sqlFragment.subSequence(matcher.start(0), matcher.end(0));
    		System.out.println("开始位置:"+matcher.start(0)+" 结束位置:"+matcher.end(0));
    		System.out.println(subSequence.toString());
    		System.out.println(e);
    		//进行替换
    		sqlFragment = sqlFragment.replaceAll("\\#E\\{"+substring+"\\}", "123123498496416");
    		//此句代码与上句代码结果一致
    //			sqlFragment = sqlFragment.replace(e, "123123");
    		
    	}
    	System.out.println(sqlFragment);
    }

结语：本人所有文章都立志写的简单易懂，戳中问题点。 当然了，简单的同时可能忽略了很多细节与详细，如有不足的地方，还请谅解并指出。  如对文章或实现技术上有问题，可联系我：qq: 1226500260     邮箱：654868284@qq.com

[https_github.com_alwaysInRoad_test-regex-demo]: https://github.com/alwaysInRoad/test-regex-demo
[https_download.csdn.net_download_weixin_40841731_10708981]: https://download.csdn.net/download/weixin_40841731/10708981