杭电oj
Problem Title 2 Pro. ID 1001
Sum Problem
#include<stdio.h>
int main()
{
int i,n,sum=0;
while(scanf("%d",&n)!=EOF){
sum=0;
for(i=1;i<=n;i++){
sum = sum + i;
}
printf("%d\n",sum);
printf("\n");
}
}
没什么特别的,记住while(scanf()!=EOF)格式。
Problem Title 2 Pro. ID 1001
Sum Problem
#include<stdio.h>
int main()
{
int i,n,sum=0;
while(scanf("%d",&n)!=EOF){
sum=0;
for(i=1;i<=n;i++){
sum = sum + i;
}
printf("%d\n",sum);
printf("\n");
}
}
没什么特别的,记住while(scanf()!=EOF)格式。
密码 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Picture Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Othe
Bellovin Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/O
Palindrome Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/O
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逃生 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
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