Struts2跳转页面（action）设置为动态

不念不忘少年蓝@ 2022-05-17 03:19 173阅读 0赞

**LoginAction:动态链接的设置**

package com.zs.action;
    
    import java.util.Random;
    
    import javax.servlet.http.HttpServletRequest;
    
    import org.apache.struts2.ServletActionContext;
    
    import com.opensymphony.xwork2.ActionSupport;
    
    public class LoginAction extends ActionSupport{ 
    //动态跳转页面
        private String uname;
        private String upwd;
        private String url;
    
    
        public String getUname() {
            return uname;
        }
    
        public void setUname(String uname) {
            this.uname = uname;
        }
    
    
        public String getUpwd() {
            return upwd;
        }
    
    
        public void setUpwd(String upwd) {
            this.upwd = upwd;
        }
    
    
        public String getUrl() {
            return url;
        }
    
    
        public void setUrl(String url) {
            this.url = url;
        }
    
    
        public String test() {
            uname="admin";
            upwd="123";
            Random myr=new Random();
            int r=myr.nextInt(2);
            if(r==1) {
                url = "test1.jsp";
            }
            else {
                url = "test.jsp";
            }
            return SUCCESS;
        }
    }

**xml里面的action配置:**

<action name="LoginAction" class="com.zs.action.LoginAction" method="test">
              
              <result type="redirect">
                  <param name="uname">${uname}</param>
                  <param name="upwd">${uname}</param>
                  <param name="location">${url}</param>
              </result>
    </action>

**注意事项：**  
\*\*result的type类型要是redirect，以便动态改变地址栏  
这一截要写在result里面  
location这个不能乱取名字，必须是它\*\*

<param name="uname">${uname}</param>
     <param name="upwd">${uname}</param>
     <param name="location">${url}</param>

**说在最后的话：编写实属不易，若喜欢或者对你有帮助记得点赞+关注或者收藏哦~**