0x2 Python学习之路之Python列表、元组操作

妖狐艹你老母 2022-05-18 11:17 191阅读 0赞

# 列表、元组操作 #

--------------------

## 列表 ##

### 定义列表： ###

names = ["China", "ShanDong", "LiaoCheng", "University"]

通过下标访问列表中的元素，下标从0开始计数

names = ["China", "ShanDong", "LiaoCheng", "University"]
    print(names[0],names[2])#打印第一个names,打印下标为2的names

### **切片：取多个元素** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    print(names[1:3])#切片
    print(names[0:3])#切片
    print(names[-1])
    print(names[-2:0])#print(names[-2:])
    print(names[0:3])#print(names[:3])
    
    输出：
    ['ShanDong', 'LiaoCheng']
    ['China', 'ShanDong', 'LiaoCheng']
    University
    []
    ['China', 'ShanDong', 'LiaoCheng']

### **追加：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names.append("Dadaghe")#放到尾部
    print(names)
    #['China', 'ShanDong', 'LiaoCheng', 'University', 'Dadaghe']

### **插入：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names.insert(1,"LiaoCheng")#插在下标1前面
    names.insert(3,"ShanDong")#插在下标3前面
    print(names)
    #['China', 'LiaoCheng', 'ShanDong', 'ShanDong', 'LiaoCheng', 'University']

### **修改：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names[2] = "QingHua"
    print(names)
    #['China', 'ShanDong', 'QingHua', 'University']

### **删除：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    #names.remove("LiaoCheng")
    del names[3]
    #names.pop(1) =del names[1]
    print(names)
    #['China', 'ShanDong', 'LiaoCheng']

### **获取下标：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    print(names.index("ShanDong"))#获取ShanDong下标
    print(names[names.index("ShanDong")])#获取到ShanDong下标然后输入下标对应的names  其实这句话有点智障，哈哈
    #1
    #ShanDong

### **统计：** ###

names = ["China", "ShanDong", "LiaoCheng", "University","ShanDong"]
    print(names)
    print(names.count("ShanDong"))
    #['China', 'ShanDong', 'LiaoCheng', 'University', 'ShanDong']
    #2

### **清空：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names.clear()
    print(names)

### **反转：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names.reverse()
    print(names)
    #['University', 'LiaoCheng', 'ShanDong', 'China']

### **排序：** ###

names = ["4China", "ShanDong", "#!LiaoCheng", "University"]
    names.sort()
    print(names)
    #['#!LiaoCheng', '4China', 'ShanDong', 'University']按照ASCII码进行排序

### **扩展：** ###

names = ["China", "ShanDong", "LiaoCheng", "University"]
    names2 = [1,2,3,4]
    names.extend(names2)
    #del names2 //删除列表nemes2
    print(names)
    print(names2)
    #['China', 'ShanDong', 'LiaoCheng', 'University', 1, 2, 3, 4]
    #[1, 2, 3, 4]

## **元组** ##

元组其实跟列表差不多，也是存一组数，只不是它一旦创建，便不能再修改，所以又叫只读列表

语法

names = ("China", "ShanDong", "LiaoCheng", "University")

它只有2个方法，一个是count,一个是index，完毕。

names = ("China", "ShanDong", "LiaoCheng", "University")
    print(names.count("China"))
    #1

#功能：获取元素在元组中的索引值,对于重复的元素,默认获取从左起第一个元素的索引值
    names = ("China", "ShanDong", "LiaoCheng", "University","a","b")
    T = names.index("a")
    print(T)
    #4