java使用正则表示式限制特殊字符的个数

谁借莪１个温暖的怀抱￠ 2022-05-18 22:46 93阅读 0赞

package com.l.dubbo.service;
    
    import java.util.HashSet;
    import java.util.Set;
    import java.util.regex.Matcher;
    import java.util.regex.Pattern;
    
    public class ThreadPoolTest {
        public static boolean check1(String context, String regEx) {
            Pattern pattern = Pattern.compile(regEx);
            Matcher matcher = pattern.matcher(context);
            String ss = "";
            String s2 = "";
            boolean flag = true;
            int count = 0;
            //符合正则表达式的子段为特殊符号
            //比较子段是否重复  若重复则特殊符号种类不止一种
            while (matcher.find()) {
                if (count == 0) {
                    ss = matcher.group();
    //                System.out.println(ss);
                } else {
                    s2 = matcher.group();
    //                System.out.println(s2);
                }
                if (!(ss).equals(s2) && count > 0) {
                    flag = false;
                }
                count++;
            }
    //        System.out.println(count);
            return flag;
        }
    
        public static boolean check2(String context, String regEx) {
            Pattern pattern = Pattern.compile(regEx);
            Matcher matcher = pattern.matcher(context);
            boolean flag = false;
            //利用set的元素不能重复，来检查是否只有一种特殊符号
            Set<String> set = new HashSet<String>();
            while (matcher.find()) {
                set.add(matcher.group());
            }
            if (set.size() == 1) {
                flag = true;
            }
            return flag;
        }
    
        public static void main(String[] args) {
            //s1中只包含’！‘一种特殊字符
            String s1 = "dasd!a22!!!!";
            //s2中包含’！‘和’@‘两种特殊字符
            String s2 = "dasd!a22@!!!";
            String regEx = "((?=[\\x21-\\x7e]+)[^A-Za-z0-9])";
            System.out.println(check1(s1, regEx));
            System.out.println(check1(s2, regEx));
            System.out.println(check2(s1, regEx));
            System.out.println(check2(s2, regEx));
        }
    }

输出结果

true
    false
    true
    false
    
    Process finished with exit code 0