汇编：从键盘录入20个数（-128~127），求最大值

「爱情、让人受尽委屈。」 2022-05-24 12:11 183阅读 0赞

include 一套工具.mac
    data segment
    	show db "Please Input twenty numbers:$"
    	iit1 db "The $"
    	iit2 db " number is:$"
    	buf db 20 dup(?)
    	x   db ?,?,?,?  ;x[0]用来存负号
    	w   db ?  ;用于显示提示信息
    	max db ?
    	boundary db "128$"
    	display db "Max:$"
    	error1 db "Input error!<you can check whether it is between -128~127>",13,10,"Please Input again:$"
    data ends
    
    stack segment
    
    stack ends
    
    code segment
    assume ds:data,cs:code,ss:stack
    start:
    	mov ax,data
    	mov ds,ax
    	mov ax,stack
    	mov ss,ax
    	
    	mov bx,0
    	push bx
    	mov bx,1
    			;显示提示输入信息
    	oustring show
    	ld
    inpu1:     ;显示提示输入信息
    	oustring iit1
    	
    	inc w
    	cmp w,9
    	jg www
    	mov dl,w
    	add dl,30h
    	mov ah,2
    	int 21h
    	
    	oustring iit2
    set1:   ;输入
    	input
    	cmp al,1bh   ;ESC退出
    	jz exit
    	cmp al,13      ;回车
    	jz outpu1
    	
    	cmp al,'-'
    	jz minus
    	          ;判断是否在0-9
    	cmp al,30h
    	jl error0
    	cmp al,39h
    	jg error0
    	
    	cmp bx,4
    	jg error0
    	
    	sub al,30h
    	mov x[bx],al ;输入的字符合法，从x[1]开始存
    	inc bx
    	jmp set1
    
    minus:
    	cmp x[0],0
    	jnz error0    ;负号已存在则输出错误信息
    	mov x[0],al  ;把负号存入x[0]中
    	jmp set1
    	
    outpu1:
    	cmp bx,1
    	jz error0
    	cmp x[0],'-'      
    	jz negativedealwith
    
    	cmp bx,2
    	jz onedigit
    	cmp bx,3
    	jz twodigit
    	
    	mov al,x+1
    	mov cl,100
    	imul cl
    	mov bl,al
    	mov al,x+2
    	mov cl,10
    	imul cl
    	add al,x+3
    	mov bh,0
    	cbw
    	add ax,bx
    	cmp ax,127
    	jg error0
    	
    	pop bx
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    	
    onedigit:
    	pop bx
    	mov al,x+1
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    	
    twodigit:
    	mov al,x+1
    	mov cl,10
    	imul cl
    	add al,x+2
    	
    	pop bx
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    	
    negativedealwith:
    	cmp bx,2
    	jz onebit
    	cmp bx,3
    	jz twobit
    	
    	mov al,x+1
    	mov cl,100
    	imul cl
    	mov bl,al
    	mov al,x+2
    	mov cl,10
    	imul cl
    	add al,x+3
    	mov bh,0
    	cbw
    	neg ax
    	neg bx
    	add ax,bx
    	cmp ax,-128
    	jl error0
    	
    	pop bx
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    	
    onebit:
    	mov al,x+1
    	neg al
    	pop bx
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    
    twobit:
    	mov al,x+1
    	mov cl,10
    	imul cl
    	add al,x+2
    	neg al
    	
    	pop bx
    	mov buf[bx],al
    	inc bx
    	cmp bx,19
    	jg outpu2
    	push bx
    	;清0
    	jmp clear
    	
    clear:
    	;清0操作
    	mov bx,0
    	mov cx,4
    re2:
    	mov x[bx],0
    	inc bx
    	loop re2
    	mov bx,1
    	ld
    	jmp inpu1
    	
    error0:    ;输入错误
    	ld
    	oustring error1
    	
    	;关键的一步，清0操作
    	mov bx,0
    	mov cx,4
    re1:
    	mov x[bx],0
    	inc bx
    	loop re1
    	mov bx,1
    	jmp set1
    	
    www:     ;显示提示输入信息
    	mov al,w
    	cbw
    	mov cl,10
    	idiv cl
    	mov cl,ah
    	add al,30h
    	output al
    	add cl,30h
    	output cl
    	
    	oustring iit2
    	jmp set1
    	
    outpu2:
    	ld
    	oustring display
    	
    	mov cx,19
    	mov bx,0
    	mov al,buf[bx]
    set2:
    	cmp al,buf[bx+1]
    	jl exchange
    	inc bx
    	loop set2
    	jmp outpu3
    exchange:
    	mov al,buf[bx+1]
    	inc bx
    	loop set2
    outpu3:
    	mov max,al
    	cmp max,0
    	jl minusout
    outpu4:
    	cmp max,10
    	jl oneout1
    	cmp max,100
    	jl twoout1
    	
    	mov al,max
    	cbw
    	mov cl,100
    	idiv cl
    	mov cl,ah
    	add al,30h
    	output al
    	mov al,cl
    	cbw
    	mov cl,10
    	idiv cl
    	mov cl,ah
    	add al,30h
    	output al
    	add cl,30h
    	output cl
    	jmp exit
    	
    oneout1:
    	add max,30h
    	output max
    	jmp exit
    
    twoout1:
    	mov al,max
    	cbw
    	mov cl,10
    	idiv cl
    	mov cl,ah
    	mov dl,al
    	add dl,30h
    	mov ah,2
    	int 21h
    	add cl,30h
    	output cl
    	jmp exit
    	
    minusout:
    	output '-'
    	cmp max,-128
    	jz outpu5
    	neg max
    	jmp outpu4
    	
    outpu5:
    	oustring boundary
    exit:
    	mov ah,4ch
    	int 21h
    code ends
    end start

运行结果如下：

1.边界检测：

![20180526233520539][]

![20180526233524864][]

2.三位数之间的比较检测：

![20180526233905975][]

![20180526234012506][]

![2018052623413171][]

![20180526234329930][]

3.两位数之间比较检测：

![20180526234507951][]

![20180526234746192][]

4.一位数比较检测：

![20180526234955982][]

![20180526235002410][]

5.综合检测：

![20180526235033387][]

[20180526233520539]: /images/20220524/acfa518f3edb4e50867801fff794e2c6.png
[20180526233524864]: /images/20220524/e5afebe18ef7430d93623bb54d78beb2.png
[20180526233905975]: /images/20220524/6a10d81f13324033b66295851397d580.png
[20180526234012506]: /images/20220524/75b1d793867740e3bc877c5620b9571e.png
[2018052623413171]: /images/20220524/0e98fae5890b429091791df79b4ff5ab.png
[20180526234329930]: /images/20220524/ad1e90eb7bf64c478e93a9906e2838b7.png
[20180526234507951]: /images/20220524/18b885e63fa44d53abfae5bec6f7b5a0.png
[20180526234746192]: /images/20220524/0c3eb2b5deaa4e358286bfdfd78ec558.png
[20180526234955982]: /images/20220524/b31063a708ec4e2baebf45bc2cfc70d7.png
[20180526235002410]: /images/20220524/d79ac2494464478f8c2d896010374525.png
[20180526235033387]: /images/20220524/df8147501245489c859edc6cf5c4fa67.png