1105. Spiral Matrix (25)-蒲公英云

1105. Spiral Matrix (25)

This time your job is to fill a sequence of N positive integers into a spiral matrix in non-increasing order. A spiral matrix is filled in from the first element at the upper-left corner, then move in a clockwise spiral. The matrix has m rows and n columns, where m and n satisfy the following: m*n must be equal to N; m>=n; and m-n is the minimum of all the possible values.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N. Then the next line contains N positive integers to be filled into the spiral matrix. All the numbers are no more than 104. The numbers in a line are separated by spaces.

Output Specification:

For each test case, output the resulting matrix in m lines, each contains n numbers. There must be exactly 1 space between two adjacent numbers, and no extra space at the end of each line.

Sample Input:

12
37 76 20 98 76 42 53 95 60 81 58 93

Sample Output:

题目大意：

代码：

#include<stdio.h>
#include<algorithm>
#include<math.h>
using namespace std;
bool cmp(int a,int b)
{
    return a>b;
}
int a[100000];
int b[10000][10000];
int main()
{
    int n,m,k,t=0;
    scanf("%d",&n);
    k= sqrt((double)n);
    while(k>1) {
        if(n % k == 0)
            break;
        k--;
    }
    m=n/k;
    for(int i=0;i<n;i++)
    {
        scanf("%d",&a[i]);
    }
    sort(a,a+n,cmp);
    for (int i=0;t<n;i++) {
        for (int j=i;j<k-i&&t<n;j++)
                b[i][j]=a[t++];
        for (int j=i+1;j<m-1-i&&t<n;j++)
                b[j][k-1-i]=a[t++];
        for (int j=k-i-1;j>=i &&t<n;j--)
                b[m-1-i][j]=a[t++];
        for (int j=m-2-i;j>=i+1&&t<n;j--)
                b[j][i]=a[t++];
    }
        for(int i=0;i<m;i++)
        {
            for(int j=0;j<k;j++)
            {
                if(j==0)
                {
                    printf("%d",b[i][j]);
                }
                else
                {
                    printf(" %d",b[i][j]);
                }
            }
            printf("\n");
        }
}