【javaweb：Servlet】显示用户访问时间-demo

浅浅的花香味﹌ 2022-06-01 05:10 133阅读 0赞

package indi.lastAccesstime;
    
    import java.io.IOException;
    import java.text.SimpleDateFormat;
    import java.util.Date;
    
    import javax.servlet.ServletException;
    import javax.servlet.http.Cookie;
    import javax.servlet.http.HttpServlet;
    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
    
    public class LastAccessTimeServlet extends HttpServlet {
    
    	public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    		//1.每次访问时都要创建当前访问时间的cookie，并发给客户端
    		Date date=new Date();
    		//注意：TomCat8.5版本中时间不能有空格，否则不能创建cookie！！！！！
    		SimpleDateFormat format=new SimpleDateFormat("yyyy-MM--dd/hh:mm:ss");
    		String currentTime=format.format(date);
    		Cookie cookie=new Cookie("lastAccessTime", currentTime);
    		System.out.println(currentTime);
    		//设置cookie在客户端硬盘的保存时间
    		cookie.setMaxAge(60*10*20);
    		//将cookie发送给客户端
    		response.addCookie(cookie);
    		
    		//2.从客户端获取上次访问时间的cookie，并根据是否是第一次访问打印不同的语句
    		String lastAccessTime=null;
    		Cookie[] cookies = request.getCookies();
    		if(cookies!=null) {
    			for(Cookie coo:cookies) {
    				if("lastAccessTime".equals(coo.getName())) {
    					lastAccessTime=coo.getValue();
    				}
    			}
    		}
    		//设置response的解码字符集为UTF-8
    		response.setContentType("text/html;charset=UTF-8");
    		if(lastAccessTime!=null) {
    			response.getWriter().write("您上次的访问时间是:"+lastAccessTime);
    		}else {
    			response.getWriter().write("这是您的第一次访问！");
    		}
    	}
    
    	public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    		doGet(request, response);
    	}
    }