ZOJ 3767 Elevator（水题）

逃离我推掉我的手 2022-06-03 08:59 110阅读 0赞

How time flies! The graduation of this year is around the corner. N members of ZJU ACM/ICPC Team decided to hold a party in a restaurant. The restaurant is located in a skyscraper so they need to take an elevator to reach there.

The elevator's maximum load is M kilograms. The weight of the i-th team member is Aikilograms. If the total weight of people in the elevator exceeds the maximum load of the elevator, the elevator will raise the alarm and will not move.

Please write a program to implement the weight detector of the elevator.

Input

There are multiple test cases. The first line of input is an integer T indicates the number of test cases. For each test case:

The first line contains two integers N (1 <= N <= 20) and M (1 <= M <= 2000). The next line contains N integers Ai (1 <= Ai <= 500).

Output

For each test case, output "Safe" if no alarm will be raised. Otherwise, output "Warning".

Sample Input

2
    3 800
    50 60 70
    9 800
    50 55 60 60 60 60 65 70 360

Sample Output

Safe
    Warning

题解：

很水的一题，贴诗：

静夜思  
李白  
床前明月光，疑是地上霜。  
举头望明月，低头思故乡。

代码：

#include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    #include<queue>
    #include<stack>
    #include<math.h>
    #include<vector>
    #include<map>
    #include<set>
    #include<stdlib.h>
    #include<cmath>
    #include<string>
    #include<algorithm>
    #include<iostream>
    #include<stdio.h>
    using namespace std;
    #define ll long long
    #define maxn 100008
    int main()
    {
        int test,i,j,n,m,s,x;
        while(scanf("%d",&test)!=EOF)
        {
            while(test--)
            {
                s=0;
                scanf("%d%d",&n,&m);
                for(i=0;i<n;i++)
                {
                    scanf("%d",&x);
                    s+=x;
                }
                if(s>m)
                {
                    printf("Warning\n");
                }
                else
                    printf("Safe\n");
            }
        }
        return 0;
    }