leetcode 461. Hamming Distance 汉明距离 + 位运算
The Hamming distance between two integers is the number of positions at which the corresponding bits are different.
Given two integers x and y, calculate the Hamming distance.
Note:
0 ≤ x, y < 231.
Example:
Input: x = 1, y = 4
Output: 2
Explanation:
1 (0 0 0 1)
4 (0 1 0 0)
↑ ↑
The above arrows point to positions where the corresponding bits are different.
汉明码,就是位操作
代码如下:
#include <iostream>
#include <vector>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <string>
#include <climits>
#include <algorithm>
#include <sstream>
#include <functional>
#include <bitset>
#include <cmath>
using namespace std;
class Solution
{
public:
int hammingDistance(int x, int y)
{
int dist = 0, n = x ^ y;
while (n>0)
{
++dist;
n &= n - 1;
}
return dist;
}
};
还没有评论,来说两句吧...