GCC 编译 -std简述

悠悠 2022-06-14 08:00 271阅读 0赞

用GCC编译代码时候后面带有-std=c++1z 的选项，这是指定c/c++的标准.具体的标准如下，详细信息可以看引用里面的详细说明

# c #

<table> 
 <thead> 
  <tr> 
   <th>stand</th> 
   <th align="left">descript</th> 
  </tr> 
 </thead> 
 <tbody> 
  <tr> 
   <td>-std=c90 or -std=iso9899:1990</td> 
   <td align="left">称为C89或C90</td> 
  </tr> 
  <tr> 
   <td>-std=iso9899:199409</td> 
   <td align="left">称为C94或C95</td> 
  </tr> 
  <tr> 
   <td>-std=c99 or -std=iso9899:1999.</td> 
   <td align="left">1999年发布的 ISO/IEC 9899:1999，称为C99</td> 
  </tr> 
  <tr> 
   <td>-std=c11 or -std=iso9899:2011</td> 
   <td align="left">称为C11</td> 
  </tr> 
  <tr> 
   <td>-std=gnu90</td> 
   <td align="left">C90和GNU扩展</td> 
  </tr> 
  <tr> 
   <td>-std=gnu99</td> 
   <td align="left">C99和GNU扩展</td> 
  </tr> 
  <tr> 
   <td>-std=gnu11</td> 
   <td align="left">C11和GNU扩展</td> 
  </tr> 
 </tbody> 
</table>

# c++ #

<table> 
 <thead> 
  <tr> 
   <th>stand</th> 
   <th align="left">descript</th> 
  </tr> 
 </thead> 
 <tbody> 
  <tr> 
   <td>-std=c++98, or -std=c++03</td> 
   <td align="left">称为 C++98</td> 
  </tr> 
  <tr> 
   <td>-std=c++11</td> 
   <td align="left">称为C++11</td> 
  </tr> 
  <tr> 
   <td>-std=c++14</td> 
   <td align="left">称为C++14</td> 
  </tr> 
  <tr> 
   <td>-std=c++17 or -std=c++1z</td> 
   <td align="left">称为C++17</td> 
  </tr> 
  <tr> 
   <td>-std=gnu++98</td> 
   <td align="left">C++98和GNU扩展</td> 
  </tr> 
  <tr> 
   <td>-std=gnu++11</td> 
   <td align="left">C++11和GNU扩展</td> 
  </tr> 
  <tr> 
   <td>-std=gnu++14</td> 
   <td align="left">C++14和GNU扩展</td> 
  </tr> 
  <tr> 
   <td>-std=gnu++1z</td> 
   <td align="left">C++17和GNU扩展</td> 
  </tr> 
 </tbody> 
</table>

# 引用 #

> [https://gcc.gnu.org/onlinedocs/gcc/Standards.html][https_gcc.gnu.org_onlinedocs_gcc_Standards.html]

[https_gcc.gnu.org_onlinedocs_gcc_Standards.html]: https://gcc.gnu.org/onlinedocs/gcc/Standards.html