ECharts异步获取数据

素颜马尾好姑娘i 2022-06-15 12:09 217阅读 0赞

<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%>
    <!DOCTYPE html>
    <html>
    <head>
    <meta charset="utf-8">
    <title>Insert title here</title>
    <script type="text/javascript" src="static/js/jquery-3.1.1.min.js"></script>
    <script type="text/javascript" src="static/js/echarts.js"></script>
    
    </head>
    <body>
     <div id="main" style="width: 1000px;height:400px;"></div>
    
    <script> var myChart = echarts.init(document.getElementById('main')); // 指定图表的配置项和数据 $.get("json_test").done(function(obj){ var datas = JSON.parse(obj);//将json字符串转换成json对象 console.log(datas.series[1]); var dataNam=[]; for(var i=0;i<datas.series.length;i++){ dataNam.push(datas.series[i].name); } myChart.setOption({ title: { text: datas.title }, tooltip: {}, legend: { data:dataNam }, xAxis: { data: datas.xName }, yAxis: {}, series: datas.series }); }) </script>   
    </body>
    </html>

后台代码

@ResponseBody
        @RequestMapping("/json_test")
        public Object thisIsTest(){
            try {
                BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream("C:/Users/Administrator/Desktop/test.json"),"utf-8"));
    
                try {
    
                    StringBuilder sb = new StringBuilder();
                    String data = null;
                    while ((data = br.readLine())!=null) {
                        sb.append(data);
                    }
                    System.out.println(sb.toString());
                    return sb.toString();
                } catch (IOException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }
    
    
    
            } catch (Exception e) {
                e.printStackTrace();
            }
            return null;
        }