java练习第二天hdoj1002-A + B Problem II【大数】

小咪咪 2022-07-14 20:37 132阅读 0赞

# A + B Problem II #

**Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)  
Total Submission(s): 328163 Accepted Submission(s): 63712**

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case \#:", \# means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

2
    1 2
    112233445566778899 998877665544332211

Sample Output

Case 1:
    1 + 2 = 3
    
    Case 2:
    112233445566778899 + 998877665544332211 = 1111111111111111110
      
       
      
       
       
        import java.math.BigInteger;
    import java.util.Scanner;
    
    
    public class Main {
    	
    	public static void main(String [] args) {
    		
    		Scanner cin=new Scanner(System.in);
    		int t;
    		t=cin.nextInt();
    		for(int i=1;i<=t;i++){
    			BigInteger a = cin.nextBigInteger();  
    			BigInteger b = cin.nextBigInteger();  
    			//System.out.println(i);
    			System.out.println("Case "+i+":");
    			System.out.println(a+" + "+b+" = "+a.add(b));
    			if(i<t){
    				System.out.println();
    			}
    		}
    	}
    
    }