4-1 复数类的运算符重载

灰太狼 2022-07-16 00:15 145阅读 0赞

### 4-1 复数类的运算符重载 ###

Time Limit: 1000MS Memory Limit: 65536KB

[Submit][] [Statistic][]

#### Problem Description ####

通过本题目的练习可以掌握成员运算符重载及友元运算符重载

要求定义一个复数类，重载加法和减法运算符以适应对复数运算的要求，重载插入运算符(<<)以方便输出一个复数的要求。

#### Input ####

要求在主函数中创建对象时初始化对象的值。

#### Output ####

输出数据共有4行，分别代表a，b的值和它们求和、求差后的值

#### Example Input ####

无

#### Example Output ####

a=3.2+4.5i
    b=8.9+5.6i
    a+b=12.1+10.1i
    a-b=-5.7-1.1i

#### Hint ####

#include <iostream>
    #include <algorithm>
    using namespace std;
    
    class  Complex
    {
    private:
        double x;
        double y;
    public:
        Complex(){x=0,y=0;}//如果主函数定义的对象都有参数可以不用这一句,若定义无餐对象则不能丢
        Complex(double a,double b){x=a,y=b;}
        Complex operator + (Complex &c2);//声明重载运算符
        Complex operator - (Complex &c2);
       void display1()
       {
           cout<<"a="<<x<<"+"<<y<<"i"<<endl;
       }
       void display2()
       {
            cout<<"b="<<x<<"+"<<y<<"i"<<endl;
       }
       void display3()
       {
            cout<<"a+b="<<x<<"+"<<y<<"i"<<endl;
       }
       void display4()
       {
            cout<<"a-b="<<x<<y<<"i"<<endl;
       }
    };
    
    Complex Complex::operator +(Complex &c2)
    {
        Complex c;
        c.x=x+c2.x;
        c.y=y+c2.y;
        return c;
    }
    
    Complex Complex::operator -(Complex &c2)
    {
        Complex c;
        c.x=x-c2.x;
        c.y=y-c2.y;
        return c;
    }
    
    int main()
    {
        Complex c1(3.2,4.5),c2(8.9,5.6),c3,c4;
        c1.display1();
        c2.display2();
        c3=c1+c2;
        c4=c1-c2;
        c3.display3();
        c4.display4();
        return 0;
    }

[Submit]: http://www.sdutacm.org/onlinejudge2/index.php/Home/Contest/contestsubmit/cid/1819/pid/2677.html
[Statistic]: http://www.sdutacm.org/onlinejudge2/index.php/Home/Contest/conteststatus/cid/1819/pid/2677.html