解决 IDEA 发布到 Tomcat 项目的 404 和相对路径问题

以你之姓@ 2022-07-16 10:12 152阅读 0赞

情况总体分为两种:

*  #### idea配置问题, ####
 *  #### java代码比如 springmvc 配置问题 ####

### IDEA配置问题: ###

比如我有个项目是AAA，用eclipse发到tomcat上，路径应该是 [xxx.com/AAA,但使用了IDEA，访问xxx.com/AAA就会报404的错误.但编译出来的WAR直接丢到TOMCAT上又是正常的。][xxx.com_AAA_IDEA_xxx.com_AAA_404_._WAR_TOMCAT]  
下面是解决方案，其实很简单，2选1就行了，我个人倾向于第1种方案.

1.![这里写图片描述][aHR0cDovL2ltZy5ibG9nLmNzZG4ubmV0LzIwMTYxMDE0MTYwMzI1MDg1]

2.![这里写图片描述][aHR0cDovL2ltZy5ibG9nLmNzZG4ubmV0LzIwMTYxMDE0MTYwMzQwMjI2]

### SpringMvc 配置问题 ###

查看你的dispatcher-servlet.xml里的配置项,主要这里的base packge一定要和你自己controller所在的包名称一致,如果这里配置错了,一样也会导致404  
类似如下

<context:component-scan base-package="com.test">--
        </context:component-scan>

同时可以观察tomcat启动以后在idea终端里的日志,会有如下输出,说明识别了controller

org.springframework.web.servlet.handler.AbstractHandlerMethodMapping.registerHandlerMethod Mapped "{[/manage/category/set_category_name.do],methods=[],params=[],headers=[],consumes=[],produces=[],custom=[]}" onto public com.mmall.common.ServerResponse com.mmall.controller.backend.CategoryManageController.setCategoryName(javax.servlet.http.HttpServletRequest,java.lang.Integer,java.lang.String)
    org.springframework.web.servlet.handler.AbstractHandlerMethodMapping.registerHandlerMethod Mapped "{[/manage/category/get_category.do],methods=[],params=[],headers=[],consumes=[],produces=[],custom=[]}" onto public

[xxx.com_AAA_IDEA_xxx.com_AAA_404_._WAR_TOMCAT]: http://xxx.com/AAA,%E4%BD%86%E4%BD%BF%E7%94%A8%E4%BA%86IDEA%EF%BC%8C%E8%AE%BF%E9%97%AExxx.com/AAA%E5%B0%B1%E4%BC%9A%E6%8A%A5404%E7%9A%84%E9%94%99%E8%AF%AF.%E4%BD%86%E7%BC%96%E8%AF%91%E5%87%BA%E6%9D%A5%E7%9A%84WAR%E7%9B%B4%E6%8E%A5%E4%B8%A2%E5%88%B0TOMCAT%E4%B8%8A%E5%8F%88%E6%98%AF%E6%AD%A3%E5%B8%B8%E7%9A%84%E3%80%82
[aHR0cDovL2ltZy5ibG9nLmNzZG4ubmV0LzIwMTYxMDE0MTYwMzI1MDg1]: /images/20220716/f467a1239fc1442c89ca7d65ba388cb9.png
[aHR0cDovL2ltZy5ibG9nLmNzZG4ubmV0LzIwMTYxMDE0MTYwMzQwMjI2]: /images/20220716/5857ad466c1140d384ac7a5869685e6e.png