leetcode 226. Invert Binary Tree
Invert a binary tree.
4
/ \
2 7
/ \ / \
1 3 6 9
to
4
/ \
7 2
/ \ / \
9 6 3 1
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root==NULL)
return NULL;
vector<TreeNode*>que;
que.push_back(root);
while(!que.empty())
{
vector<TreeNode*>newque;
for(int i=0;i<que.size();i++)
{
if(que[i]->left!=NULL)
newque.push_back(que[i]->left);
if(que[i]->right!=NULL)
newque.push_back(que[i]->right);
}
for (int i = 0; i < que.size(); i++)
{
TreeNode*l = que[i]->left;
que[i]->left = que[i]->right;
que[i]->right = l;
}
que=newque;
}
return root;
}
};
accept
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