LeetCode-Implement Stack using Queues
Implement the following operations of a stack using queues.
- push(x) — Push element x onto stack.
- pop() — Removes the element on top of the stack.
- top() — Get the top element.
- empty() — Return whether the stack is empty.
Notes:
- You must use only standard operations of a queue — which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
一个队列即可完成,上代码:
class MyStack {
LinkedList<Integer> queue = new LinkedList<Integer>();
// Push element x onto stack.
public void push(int x) {
queue.add(x);
for (int i = 0; i < queue.size()-1; i++) {
queue.add(queue.poll());
}
}
// Removes the element on top of the stack.
public void pop() {
queue.poll();
}
// Get the top element.
public int top() {
return queue.peek();
}
// Return whether the stack is empty.
public boolean empty() {
return queue.isEmpty();
}
}
主要是每次push的时候,其实已经把入队列的顺序给reverse了。用两个队列也可以实现,但是复杂程度实在是太高了,就不展示了
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