public int addDigits(int num) {while (num > 9) {num = func(num);}return num;}public static int func(int n) {int temp = 0;while (n > 0) {temp += (n % 10);n = n / 10;}return temp;}
没有实现：
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
leetcode-258.Add Digits Given a non-negative integer num, repeatedly add all its digi
为了保持了解比较有意思的解法算法，所以决定每天看几道LeetCode上面的题，现在开始： 题目： Given a non-negative integer num, r
Given a non-negative integer `num`, repeatedly add all its digits until the result has o
Given a non-negative integer `num`, repeatedly add all its digits until the result has o
Question 258: > Given a non-negative integer num, repeatedly add all its digits until t
1.题目描述 Given a non-negative integer num, repeatedly add all its digits until the resul
/ Given a non-negative integer num, repeatedly add all its digits until the res
Given a non-negative integer num, repeatedly add all its digits until the result has onl
Given a non-negative integer `num`, repeatedly add all its digits until the result has o
Myth丶恋晨
痛定思痛。
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