第八周上机实践项目1-实现复数类中的运算符重载（可与double型运算的“基础工程”）

偏执的太偏执、 2022-08-05 12:14 99阅读 0赞

/*
     *Copyright  (c)  2014,烟台大学计算机学院
     *All rights reserved.
     *文件名称: test.cpp
     *作        者:满星辰
     *完成日期:2015 年 4 月 28 日
     *版本号:v1.0
     *
     *问题描述:定义一个定义完整的类（是可以当作独立的产品发布，成为众多项目中的“基础工程”）。
               这样的类在(2)的基础上，扩展+、-、*、/运算符的功能，使之能与double型数据进行运算。
               设Complex c; double d; c+d和d+c的结果为“将d视为实部为d的复数同c相加”，其他-、*、/运算符类似。
     *输入描述:
     *程序输出:
     */
    #include <iostream>
    using namespace std;
    class Complex
    {
    public:
        Complex(){real=0;imag=0;}
        Complex(double r,double i){real=r; imag=i;}
        friend Complex operator+(const Complex &c1,const Complex &c2);
        friend Complex operator-(const Complex &c1,const Complex &c2);
        friend Complex operator*(const Complex &c1,const Complex &c2);
        friend Complex operator/(const Complex &c1,const Complex &c2);
        friend Complex operator+(const double d,const Complex &c2);
        friend Complex operator-(const double d,const Complex &c2);
        friend Complex operator*(const double d,const Complex &c2);
        friend Complex operator/(const double d,const Complex &c2);
        friend Complex operator+(const Complex &c2,const double d);
        friend Complex operator-(const Complex &c2,const double d);
        friend Complex operator*(const Complex &c2,const double d);
        friend Complex operator/(const Complex &c2,const double d);
        void display();
    private:
        double real;
        double imag;
    };
    //下面定义成员函数
    void Complex::display()
    {
        cout<<"("<<real<<","<<imag<<"i"<<")"<<endl;
    }
    Complex operator+(const Complex &c1,const Complex &c2)
    {
        Complex c;
        c.real=c1.real+c2.real;
        c.imag=c1.imag+c2.imag;
        return c;
    }
    Complex operator-(const Complex &c1,const Complex &c2)
    {
        Complex c;
        c.real=c1.real-c2.real;
        c.imag=c1.imag-c2.imag;
        return c;
    }
    Complex operator * (const Complex &c1,const Complex &c2)
    {
        Complex c;
        c.real=c1.real*c2.real-c1.imag*c2.imag;
        c.imag=c1.real*c2.imag+c1.imag*c2.real;
        return c;
    }
    Complex operator / (const Complex &c1,const Complex &c2)
    {
        Complex c;
        c.real=(c1.real*c2.real+c1.imag*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
        c.imag=(c1.imag*c2.real-c1.real*c2.imag)/(c2.real*c2.real+c2.imag*c2.imag);
        return c;
    }
    Complex operator+(const double d,const Complex &c2)
    {
        Complex c(d,0);
        return c+c2;
    }
    Complex operator-(const double d,const Complex &c2)
    {
        Complex c(d,0);
        return c-c2;
        return c;
    }
    Complex operator*(const double d,const Complex &c2)
    {
        Complex c(d,0);
        return c*c2;
    }
    Complex operator/(const double d,const Complex &c2)
    {
        Complex c(d,0);
        return c/c2;
    }
    Complex operator+(const Complex &c2,const double d)
    {
        Complex c(d,0);
        return c+c2;
    }
    Complex operator-(const Complex &c2,const double d)
    {
        Complex c(d,0);
        return c-c2;
        return c;
    }
    Complex operator*(const Complex &c2,const double d)
    {
        Complex c(d,0);
        return c*c2;
    }
    Complex operator/(const Complex &c2,const double d)
    {
        Complex c(d,0);
        return c/c2;
    }
    //下面定义用于测试的main()函数
    int main()
    {
        Complex c1(3,4),c2(5,-10),c3;
        double d=6.9;
        cout<<"c1=";
        c1.display();
        cout<<"c2=";
        c2.display();
        c3=c1+c2;
        cout<<"c1+c2=";
        c3.display();
        c3=c1-c2;
        cout<<"c1-c2=";
        c3.display();
        c3=c1*c2;
        cout<<"c1*c2=";
        c3.display();
        c3=c1/c2;
        cout<<"c1/c2=";
        c3.display();
        c3=d+c1;
        cout<<"d+c1=";
        c3.display();
        return 0;
    }

图片：

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心得：

本来是经过一系列自定义运算来实现的，后来同学告诉我可以把double型的d当做实部为d、虚部为0的复数，然后直接利用已经重载的运算符号来做

简洁明了，真是好样的！

一开始在main函数里报错，发现我写的c3=c1+d错了，我改成了c3=d+c1就运行了

去参考了一下发现 第一个参数和第二个参数 位置不同，运算时的位置也不同，真是给这严谨的规则跪了。。。

[Center]: /images/20220805/89a48a58d94b4b7a9294a747817b8d44.png