String Reversion powered by wangbin-蒲公英云

String Reversion powered by wangbin

1001. String Reversion

Total:

Accepted:

Time Limit: 1sec Memory Limit:256MB

Description

Given a valid identifier in C programs, please write a program to reverse it by respectively reversing

each part separated by ‘’.

Input

The first line is an integer t, indicating the number of test cases.
Then there are t lines and each line contains a string. A string will contain no more than 100 characters and there is one or more ‘’.

Output

For each test case, print out the string with each part reversed.

Sample Input

Copy sample input to clipboard

nt45

_me

abc123_456

Sample Output

tn_54

_em

cba_321_654

Total:

Accepted:

以下为代码：

// The source code is licensed under Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License
// URI: http://creativecommons.org/licenses/by-nc-sa/3.0/
// All Copyright reserved by Informatic Lab of Sun Yat-sen University
int main(){
    int t;
    int i, start, end;
    string s;
    cin>>t;
    while(t--){
        cin>>s;
        start=0;
        end=s.find_first_of( '_', start );
        while ( end != string::npos ){
            for ( i = end - 1; i >= start; i-- )
                cout << s[ i ];
            cout <<'_';
            start = end + 1;
            end= s.find_first_of( '_', start );
        }
        for( i = s.size() - 1; i >= start; i-- )
            cout << s[i];
        cout<<endl;
    } 
    return 0;
}