Digital Roots

短命女 2022-08-10 04:44 53阅读 0赞

## Digital Roots ##

##### Time Limit: 1000ms Memory limit: 65536K 有疑问？点这里^\_^ #####

## 题目描述 ##

The digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.  
  
For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.

## 输入 ##

The input file will contain a list of positive integers, one per line. The end of the input will be indicated by an integer value of zero.

## 输出 ##

For each integer in the input, output its digital root on a separate line of the output.

## 示例输入 ##

24
    39
    0

## 示例输出 ##

6
    3

## 提示 ##

请注意，输入数据长度不超过20位数字。

## 来源 ##

**Greater New York 2000**  
面向对数据结构和算法不是太懂的同学

## 示例程序 ##

#include<stdio.h>  
    #include<string.h>  
    int main()  
    {  
        int i,j,n,m,b;  
        char a[30];  
        while(scanf("%s",a)&&a[0]!='0')  
        {  
            m=0;  
            n=strlen(a);  
            for(i=0;i<n;i++)  
            {  
                m+=a[i]-'0';  
            }  
            while(m>9)  
            {  
                b=0;  
                while(m>=1)  
                {  
                b+=m%10;  
                m=m/10;  
                }  
                m=b;  
            }  
    printf("%d\n",m);  
        }  
    }