写两个线程,一个线程打印1-52，另…

电玩女神 2022-08-10 14:59 126阅读 0赞

### Java --写两个线程，一个线程打印1-52，另一个线程打印字母A-Z。打印 顺序为12A34B56C……5152Z ###

2012-09-24 01:29:42| 分类： [ 默认分类][Link 1] | 标签：[java][] |举报 |字号大中小 订阅

public class ThreadDemo  
\{  
// 测试  
public static void main(String\[\] args) throws Exception  
\{  
Object obj = new Object();  
// 启动两个线程  
Thread1 t1 = new Thread1(obj);  
  
Thread2 t2 = new Thread2(obj);  
  
t1.start();  
t2.start();  
\}  
  
\}  
  
// 一个线程打印1-52  
class Thread1 extends Thread  
\{  
private Object obj;  
  
public Thread1(Object obj)  
\{  
this.obj = obj;  
\}  
  
public void run()  
\{  
synchronized (obj)  
\{  
// 打印1-52  
for (int i = 1; i < 53; i++)  
\{  
System.out.print(i \+ " ");  
if (i % 2 == 0)  
\{  
// 不能忘了 唤醒其它线程  
obj.notifyAll();  
try  
\{  
obj.wait();  
\}  
catch (InterruptedException e)  
\{  
e.printStackTrace();  
\}  
\}  
\}  
\}  
  
\}  
  
\}  
  
// 另一个线程打印字母A-Z  
class Thread2 extends Thread  
\{  
private Object obj;  
  
public Thread2(Object obj)  
\{  
this.obj = obj;  
\}  
  
public void run()  
\{  
synchronized (obj)  
\{  
// 打印A-Z  
for (int i = 0; i < 26; i++)  
\{  
System.out.print((char)('A' \+ i) \+ " ");  
// 不能忘了 唤醒其它线程  
obj.notifyAll();  
try  
\{  
// 最后一个就不要等了  
if (i != 25)  
\{  
obj.wait();  
\}  
\}  
catch (InterruptedException e)  
\{  
e.printStackTrace();  
\}  
  
\}  
  
\}  
\}  
  
\}

[Link 1]: http://tjlibaoh.blog.163.com/blog/#m=0&t=1&c=fks_084070087084085075081080080095086087080065086080082066087
[java]: http://tjlibaoh.blog.163.com/blog/#m=0&t=3&c=java