MATLAB碎纸片的拼接复原

「爱情、让人受尽委屈。」 2022-08-28 14:56 171阅读 0赞

**MATLAB碎纸片的拼接复原**

1.  **摘要**

对于只有纵切的情形，文章通过比较当前待拼碎片与剩余碎片的信噪比psnr\[1,3,4\]的值来确定两碎片是否为邻接碎片；拼接算法首先连续调用右拼函数直到拼接到原图右边界，然后连续调用左拼函数直到拼接到原图左边界，从而得到整幅复原图像；对于单面纵横交错切的情形，文章对首先采用纵切拼接算法将碎片拼接成多幅横条图片，然后将各横条图片矩阵转置\[2\]，再次采用纵切拼接算法拼接；两种情形的拼接，都存在人为参与；实验证明，我们的算法对纵切情形是有效的，对纵横切情况是可行的。

1.  **源码**

function \[y,m,flag\]=f2(a,Y,n)

i=length(n);

\[p,q\]=size(Y);

if sum(Y(:,q))>p-2

flag=0;

y=Y;

m=n;

return;

end

\[x1,x2,x3\]=size(a);

M=zeros(x1-i);

l=1;

for k=1:x1

flag=0;

for j=1:i

if k==n(j)

flag=1;

break;

end

if flag==0

M(l)=k;

l=l+1;

end

E=zeros(x1-i);

for k=1:(x1-i)

l=M(k);

b(:,:)=a(l,:,:);

Y1=Y(:,q);

b1=b(:,1);

E(k)=psnr(Y1,b1);

end

\[E1,M1\]=paixu2(E,M);

for z=x1-i:-1:1

P=M1(z);

yy(:,:)=a(P,:,:);

y=cat(2,Y,yy);

m=\[n,P\];

imwrite(y,'d:\\p.bmp','bmp');

char=input('有意义否？N\\Y','s');

if char=='Y'

flag=1;

break;

end

if char=='N'|char~='Y'

continue;

end

if char=='N'

y=Y;

m=n;

flag=0;

end

**（6）f3()函数代码**

function \[y,m,flag1\]=f3(a,Y,n)

i=length(n);

\[p,q\]=size(Y);

\[x1,x2,x3\]=size(a);

M=zeros(x1-i);

l=1;

for k=1:x1

flag=0;

for j=1:i

if k==n(j)

flag=1;

break;

end

if flag==0

M(l)=k;

l=l+1;

end

E=zeros(x1-i);

for k=1:(x1-i)

l=M(k);

b(:,:)=a(l,:,:);

Y1=Y(:,1);

b1=b(:,x3);

E(k)=psnr(Y1,b1);

end

\[E1,M1\]=paixu2(E,M);

for z=x1-i:-1:1

P=M1(z);

yy(:,:)=a(P,:,:);

y=cat(2,yy,Y);

m=\[n,P\];

imwrite(y,'d:\\p.bmp','bmp');

char=input('有意义否？N\\Y','s');

if char=='Y'

break;

end

if char=='N'| char~='Y'

continue;

end

flag1=1;

if char=='N'

y=Y;

m=n;

flag1=0;

end

**(7) paixu2()函数代码**

function \[y,z\]=paixu2(x,n)% 从小到大排序

m=size(x);

for j=1:m

for i=1:m-j

if (x(i)>x(i+1))

t=x(i);x(i)=x(i+1);x(i+1)=t;

t=n(i);n(i)=n(i+1);n(i+1)=t;

end

y=x;

z=n;

**(8) psnr()函数代码**

function s=psnr(a,b)

if size(a)~=size(b)

error('错误！两幅图像大小不一致！');

end

\[m,n\]=size(a);

a1=double(a);

b1=double(b);

sumdif=0;

max1=m\*n\*max(max(a1.^2));

for i=1:m

for j=1:n

sumdif=sumdif+(a1(i,j)-b1(i,j))^2;

end

if sumdif==0

sumdif=1;

end

s=max1/sumdif;

s=10\*log10(s);

**(9) ff()函数代码**

function \[c,C\]=ff(a,m,n)

x1=length(m);

x2=length(n);

\[a1,a2,a3\]=size(a);

l=1;

x11=x1-x2;

if x11==0

c=ones(x11);

C=ones(x11,a2,a3);

return;

end

c=ones(x11);

C=ones(x11,a2,a3);

for k=1:x1

flag=0;

for i=1:x2

if m(k)==n(i)

flag=1;

break;

end

if(flag==0)

c(l)=m(k);

mm=m(k);

C(l,:,:)=a(mm,:,:);

l=l+1;

end

**(10) pinjie1()函数代码**

function pinjie1()

a=read1();

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

**(11) pinjie2()函数代码**

function pinjie2()

a=read2();

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

**(12) pinjie3()函数代码**

function pinjie3()

a=read3();

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

y1=y';

q=length(n);

q1=int16(x/q);

t=ones(q1,q\*x2,x1);

t(1,:,:)=y1;

C=a;

\[x,x1,x2\]=size(a);

c=1:1:x;

for k=2:q1

\[c,C\]=ff(C,c,n);

\[x,x1,x2\]=size(C);

p(:,:)=C(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(C,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(C,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(C,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(C,y,n);

% fwrite(f1,y,n,'int');

end

y1=y';

t(k,:,:)=y1;

end

pin=pinjie3(t);

pin\_=pin';

imwrite(pin\_,'d:\\pp.bmp');

a=t;

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

**(13) pinjie4()函数代码**

function pinjie4()

a=read4();

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

y1=y';

q=length(n);

q1=int16(x/q);

t=ones(q1,q\*x2,x1);

t(1,:,:)=y1;

C=a;

\[x,x1,x2\]=size(a);

c=1:1:x;

for k=2:q1

\[c,C\]=ff(C,c,n);

\[x,x1,x2\]=size(C);

p(:,:)=C(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(C,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(C,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(C,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(C,y,n);

% fwrite(f1,y,n,'int');

end

y1=y';

t(k,:,:)=y1;

end

pin=pinjie3(t);

pin\_=pin';

imwrite(pin\_,'d:\\pp.bmp');

a=t;

\[x,x1,x2\]=size(a);

p(:,:)=a(1,:,:);

n=\[1\];

\[y,n,flag\]=f2(a,p,n);

flag1=1;

if flag==0

\[y,n,flag1\]=f3(a,p,n);

end

while (flag1~=0|flag~=0)&length(y(1,:))<x2\*19

if flag==1

\[y,n,flag\]=f2(a,y,n);

% fwrite(f1,y,n,'int');

else

\[y,n,flag1\]=f3(a,y,n);

% fwrite(f1,y,n,'int');

end

**三、实验结果**

（1）附件1的复原图片

![v2-99b546631774348e3163cb12a17d4e08\_b.jpg][v2-99b546631774348e3163cb12a17d4e08_b.jpg]

图1 附件1的复原图片

（2）附件2的复原图像

![v2-0db26227adc688f53fbab5fcd9471d1e\_b.jpg][v2-0db26227adc688f53fbab5fcd9471d1e_b.jpg]

图2 附件2的复原图片

(3) 附件3的复原图像出来的横条图片

![v2-f3d6d093a72be5ff3aea6f684c8f7677\_b.jpg][v2-f3d6d093a72be5ff3aea6f684c8f7677_b.jpg]

图3 附件3图片拼接时生成的横条图片一

![v2-881e48d1c0f224398dcb198148aa8948\_b.jpg][v2-881e48d1c0f224398dcb198148aa8948_b.jpg]

图4 附件3图片拼接时生成的横条图片二

![v2-ee3b00d92f4f4f94a9f939bc22aece21\_b.jpg][v2-ee3b00d92f4f4f94a9f939bc22aece21_b.jpg]

图5 附件3图片拼接时生成的横条图片三

![v2-cc505923d51c8ebe0cff6ecabe470dc7\_b.jpg][v2-cc505923d51c8ebe0cff6ecabe470dc7_b.jpg]

图6 附件3图片拼接时生成的横条图片四

![v2-553189011e150f3809d5b5984ee8ac3b\_b.jpg][v2-553189011e150f3809d5b5984ee8ac3b_b.jpg]

图7 附件3图片拼接时生成的横条图片五

![v2-60ba22e50e5efd5a59c683366418bea7\_b.jpg][v2-60ba22e50e5efd5a59c683366418bea7_b.jpg]

图8 附件3图片拼接时生成的横条图片六

![v2-5ac0d7c5abe8b43ce90e2dda35e1d4da\_b.jpg][v2-5ac0d7c5abe8b43ce90e2dda35e1d4da_b.jpg]

图9 附件3图片拼接时生成的横条图片七

![v2-759c7b2075a82d64d13ad222b7bcc891\_b.jpg][v2-759c7b2075a82d64d13ad222b7bcc891_b.jpg]

图10 附件3图片拼接时生成的横条图片八

![v2-57ed502fd2811ab5aa7075fe2206da3a\_b.jpg][v2-57ed502fd2811ab5aa7075fe2206da3a_b.jpg]

图11 附件3图片拼接时生成的横条图片九

![v2-668b3446ef0a3e0f6fb4f207e8c9077e\_b.jpg][v2-668b3446ef0a3e0f6fb4f207e8c9077e_b.jpg]

图12 附件3图片拼接时生成的横条图片十

![v2-101712435d0a8dfbb02de0eb6c648957\_b.jpg][v2-101712435d0a8dfbb02de0eb6c648957_b.jpg]

图14 附件3图片拼接时生成的横条图片十一

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