Go-实现简单的栈和队列&附加简单操作

╰半橙微兮° 2022-09-09 09:26 153阅读 0赞

代码片段如下：

/*
     *                    .::::.
     *                  .::::::::.
     *                 :::::::::::
     *             ..:::::::::::'
     *           '::::::::::::'
     *             .::::::::::
     *        '::::::::::::::..
     *             ..::::::::::::.		Utils:stack 栈和队列
     *           ``::::::::::::::::		Author:崔金朋
     *            ::::``:::::::::'        .:::.
     *           ::::'   ':::::'       .::::::::.
     *         .::::'      ::::     .:::::::'::::.
     *        .:::'       :::::  .:::::::::' ':::::.
     *       .::'        :::::.:::::::::'      ':::::.
     *      .::'         ::::::::::::::'         ``::::.
     *  ...:::           ::::::::::::'              ``::.
     * ```` ':.          ':::::::::'                  ::::..
     *  		           '.:::::'          			':'````..
     */
    
    package main
    
    import (
    	"errors"
    )
    
    type CommonStack struct {
    	stack []interface{}
    }
    
    func (s *CommonStack) CommonPush(item interface{}) (bool, error) {
    	if item == nil {
    		return false, errors.New("数据不能为空")
    	}
    
    	s.stack = append(s.stack, item)
    	return true, nil
    }
    
    func (s *CommonStack) CommonPop() (interface{}, error) {
    	length := len(s.stack)
    	var item interface{}
    	if length == 0 {
    		return item, errors.New("数据不存在")
    	} else if length == 1 {
    		item = s.stack[0]
    		s.stack = []interface{}{}
    	} else {
    		item = s.stack[length-1]
    		s.stack = s.stack[0 : length-1]
    	}
    
    	return item, nil
    }
    
    func (s *CommonStack) CommonPeek() (interface{}, error) {
    	length := len(s.stack)
    	var item interface{}
    	if length == 0 {
    		return 0, errors.New("数据不存在")
    	} else if length == 1 {
    		item = s.stack[0]
    	} else {
    		item = s.stack[length-1]
    	}
    
    	return item, nil
    }
    
    func (s *CommonStack) CommonLen() int {
    	length := len(s.stack)
    	if length == 0 {
    		return 0
    	}
    
    	return length
    }