【leetcode Database】181. Employees Earning More Than Their Managers

叁歲伎倆 2022-09-24 06:21 119阅读 0赞

题目：

The `Employee` table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.

+----+-------+--------+-----------+
    | Id | Name  | Salary | ManagerId |
    +----+-------+--------+-----------+
    | 1  | Joe   | 70000  | 3         |
    | 2  | Henry | 80000  | 4         |
    | 3  | Sam   | 60000  | NULL      |
    | 4  | Max   | 90000  | NULL      |
    +----+-------+--------+-----------+

Given the `Employee` table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
    | Employee |
    +----------+
    | Joe      |
    +----------+

解析：本题可以使用自连接来做。声明Employee表的两个别名e1和e2，然后select e1的ManagerId字段与e2的Id字段相等，且e1的Salary大于e2的Salary。代码如下：

# Write your MySQL query statement below
    SELECT e1.Name AS Employee FROM Employee AS e1,Employee AS e2 WHERE e1.ManagerId = e2.Id AND e1.Salary > e2.Salary;

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