bestcoder round#86解题报告

以你之姓@ 2022-09-26 02:56 154阅读 0赞

# Price List #

**Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/131072 K (Java/Others)  
Total Submission(s): 857 Accepted Submission(s): 454**

Problem Description

There are  n shops numbered with successive integers from  1 to  n in Byteland. Every shop sells only one kind of goods, and the price of the  i\-th shop's goods is  vi.  
  
Every day, Byteasar will purchase some goods. He will buy at most one piece of goods from each shop. Of course, he can also choose to buy nothing. Back home, Byteasar will calculate the total amount of money he has costed that day and write it down on his account book.  
  
However, due to Byteasar's poor math, he may calculate a wrong number. Byteasar would not mind if he wrote down a smaller number, because it seems that he hadn't used too much money.  
  
Please write a program to help Byteasar judge whether each number is sure to be strictly larger than the actual value.

Input

The first line of the input contains an integer  T  (1≤T≤10), denoting the number of test cases.  
  
In each test case, the first line of the input contains two integers  n,m  (1≤n,m≤100000), denoting the number of shops and the number of records on Byteasar's account book.  
  
The second line of the input contains  n integers  v1,v2,...,vn  (1≤vi≤100000), denoting the price of the  i\-th shop's goods.  
  
Each of the next  m lines contains an integer  q  (0≤q≤1018), denoting each number on Byteasar's account book.

Output

For each test case, print a line with  m characters. If the  i\-th number is sure to be strictly larger than the actual value, then the  i\-th character should be '1'. Otherwise, it should be '0'.

Sample Input

1
    3 3
    2 5 4
    1
    7
    10000

Sample Output

001

Source

[BestCoder Round \#86][BestCoder Round _86]

Recommend

wange2014 | We have carefully selected several similar problems for you: [5901][] [5900][] [5899][] [5898][] [5897][]

略水

#include<cstdio>
    #include<algorithm>
    #define LL long long
    using namespace std;
    const int N = 100000+10;
    LL a[N],b[N];
    int main() {
    	int T;
    	scanf("%d",&T);
    	while(T--) {
    		LL n,m;
    		LL sum=0,q;
    		scanf("%lld%lld",&n,&m);
    		for(int i=0; i<n; i++) {
    			scanf("%lld",&a[i]);
    			sum+=a[i];
    		}
    		for(int i=0;i<m;i++){
    			scanf("%lld",&b[i]);
    		}
    		for(int i=0;i<m;i++){
    			if(b[i]>sum)
    				printf("1");
    			else
    				printf("0");
    		}
    		printf("\n");
    	}
    	return 0;
    }

# NanoApe Loves Sequence #

**Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/131072 K (Java/Others)  
Total Submission(s): 1142 Accepted Submission(s): 467**

Problem Description

NanoApe, the Retired Dog, has returned back to prepare for the National Higher Education Entrance Examination!  
  
In math class, NanoApe picked up sequences once again. He wrote down a sequence with  n numbers on the paper and then randomly deleted a number in the sequence. After that, he calculated the maximum absolute value of the difference of each two adjacent remained numbers, denoted as  F.  
  
Now he wants to know the expected value of  F, if he deleted each number with equal probability.

Input

The first line of the input contains an integer  T, denoting the number of test cases.  
  
In each test case, the first line of the input contains an integer  n, denoting the length of the original sequence.  
  
The second line of the input contains  n integers  A1,A2,...,An, denoting the elements of the sequence.  
  
 1≤T≤10,3≤n≤100000,1≤Ai≤109

Output

For each test case, print a line with one integer, denoting the answer.  
  
In order to prevent using float number, you should print the answer multiplied by  n.

Sample Input

1
    4
    1 2 3 4

Sample Output

Source

[BestCoder Round \#86][BestCoder Round _86]

Recommend

wange2014 | We have carefully selected several similar problems for you: [5901][] [5900][] [5899][] [5898][] [5897][]

思维题

#include<cstdio>
    #include<iostream>
    #include<cstring>
    #include<cmath>
    #include<algorithm>
    #define LL long long
    using namespace std;
    const int N = 100000+10;
    int a[N],l[N],r[N];
    int main(){
    	int T,n;
    	scanf("%d",&T);
    	while(T--){
    		memset(l,0,sizeof(l));
    		memset(r,0,sizeof(r));
    		scanf("%d",&n);
    		for(int i=0;i<n;i++){
    			scanf("%d",&a[i]);
    		}
    		for(int i=1;i<n;i++){
    			l[i]=max(l[i-1],abs(a[i]-a[i-1]));
    		}
    		for(int i=n-2;i>=0;i--){
    			r[i]=max(abs(a[i]-a[i+1]),r[i+1]);
    		}
    		LL ans=0;
    		for(int i=0;i<n;i++){
    			if(i==0)
    				ans+=r[i+1];
    			else if(i==n-1)
    				ans+=l[i-1];
    			else
    				ans+=max(abs(a[i+1]-a[i-1]),max(r[i+1],l[i-1]));
    		}
    		printf("%lld\n",ans); 
    	}
    	return 0;
    }

[BestCoder Round _86]: http://acm.hdu.edu.cn/search.php?field=problem&key=BestCoder+Round+%2386&source=1&searchmode=source
[5901]: http://acm.hdu.edu.cn/showproblem.php?pid=5901
[5900]: http://acm.hdu.edu.cn/showproblem.php?pid=5900
[5899]: http://acm.hdu.edu.cn/showproblem.php?pid=5899
[5898]: http://acm.hdu.edu.cn/showproblem.php?pid=5898
[5897]: http://acm.hdu.edu.cn/showproblem.php?pid=5897