Path Sum II(C++路径总和 II)
(1)递归
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
private:
vector<vector<int>> vec;
public:
void helper(vector<int> v,TreeNode *root,int target) {
if(!root) return;
if(target-root->val==0 && !root->left && !root->right) {
v.push_back(root->val);
vec.push_back(v);
}
v.push_back(root->val);
helper(v,root->left,target-root->val);
helper(v,root->right,target-root->val);
return;
}
vector<vector<int>> pathSum(TreeNode* root, int targetSum) {
vector<int> v;
helper(v,root,targetSum);
return vec;
}
};
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