编写程序计算了整数2-20中所有整数的不含有1的因子数量，并将因子数量为奇数的整数输出出来。

妖狐艹你老母 2022-10-16 12:24 22阅读 0赞

#include<stdio.h>
    
    int get_days_of_month(int year, int month)
    {//补足函数
     
    	int days,flag;                 
    	//printf("Please input year:");   //         
    	//scanf("%d",&year);//                      
    	//printf("Please input month:"); //           
    	//scanf("%d",&month);//
    
    
    	if(year%400==0)                                  
    		flag=1;         //flag为1表示是闰年
    	else                                     
    	{ if(year%4==0&&year%100!=0)   flag=1;
    		else  flag=0;      //flag为0表示非闰年
    	}
    
    	switch(month){
    	case 1:   
    	case 3: 
    	case 5:   
    	case 7: 
    	case 8:    
    	case 10:
    	case 12: days=31;break;              
    	case 4: 
    	case 6: 
    	case 9: 
    	case 11: days=30;break; 
    	case 2:{ if(flag==1)  days=29;       
    			else days=28; } break;
    	default: printf("month input error\n");  
    	}
    
    	//printf("%d年%d月份有%d天\n",year,month,days);//
    	return  days;
    }
    
    int main(void)
    {
        int year, month, day;
        int m;
        int sum;
    
        sum = 0;
        scanf("%d %d %d", &year, &month, &day);
        for (m = 1; m <month; ++m) 
    		{
    			int days_of_month, flag;
    			//第二步：判断当前第m月份天数
    			//将当前第m月份天数赋值给days_of_month
    			days_of_month=get_days_of_month(year, m);
    			//用sum把每月的时间累加起来
    			sum += days_of_month;
    		}
    	//第三步：循环后，加上当月的日期
    	sum += day;
        printf("%d\n", sum);
    	return 0;
    }