Cannot construct instance of org.springframework.security.core.GrantedAuthority的错误解决

不念不忘少年蓝@ 2022-10-27 02:39 192阅读 0赞

# 错误描述 #

com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `org.springframework.security.core.GrantedAuthority` (no Creators, like default constructor, exist): abstract types either need to be mapped to concrete types, have custom deserializer, or contain additional type information

虽然该类实现了序列化 但是这个集合不能被解析

其实就是在spring security 权限集合反序列化失败

@Override
        public Collection<? extends GrantedAuthority> getAuthorities() { 
            List<SimpleGrantedAuthority> authorities = new ArrayList<>();
            for (Role role : roles) { 
                SimpleGrantedAuthority authority = new SimpleGrantedAuthority(role.getName());
                authorities.add(authority);
            }
            return authorities;
        }

这时候我们就需要自定义一个反序列化的类

public class CustomAuthorityDeserializer extends JsonDeserializer { 
        @Override
        public Object deserialize(JsonParser p, DeserializationContext ctxt) throws IOException, JsonProcessingException { 
            ObjectMapper mapper = (ObjectMapper) p.getCodec();
            JsonNode jsonNode = mapper.readTree(p);
            LinkedList<GrantedAuthority> grantedAuthorities = new LinkedList<>();
            Iterator<JsonNode> elements = jsonNode.elements();
            while (elements.hasNext()) { 
                JsonNode next = elements.next();
                JsonNode authority = next.get("authority");
                //将得到的值放入链表 最终返回该链表
                grantedAuthorities.add(new SimpleGrantedAuthority(authority.asText()));
            }
            return grantedAuthorities;
        }
    }

同时加上一个注解 自定义解析即可生效  
@JsonDeserialize(using = CustomAuthorityDeserializer.class)

@Override
        @JsonDeserialize(using = CustomAuthorityDeserializer.class)
        public Collection<? extends GrantedAuthority> getAuthorities() { 
            List<SimpleGrantedAuthority> authorities = new ArrayList<>();
            for (Role role : roles) { 
                SimpleGrantedAuthority authority = new SimpleGrantedAuthority(role.getName());
                authorities.add(authority);
            }
            return authorities;
        }

Cannot construct instance of org.springframework.security.core.GrantedAuthority的错误解决

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