Java怎么获取post请求参数_Java如何实现URL带请求参数(get/post)及得到get和post请求url和参数列表的方法...

怼烎@ 2022-11-08 11:48 216阅读 0赞

Java如何实现URL带请求参数(get/post)及得到get和post请求url和参数列表的方法

发布于 2020-2-29|

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本文给大家介绍Java如何实现URL带请求参数(get/post)及得到get和post请求url和参数列表的方法，涉及到

java获取post请求参数的方法，感兴趣的朋友一起看看吧

具体代码如下所示：

\`\`\`java

public static String sendGet(String url,String param)

String result = "";

try\{

String urlName = url + "?"+param;//

URL U = new URL(urlName);

URLConnection connection = U.openConnection();

connection.connect();

BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));

String line;

while ((line = in.readLine())!= null)

result += line;

in.close();

\}catch(Exception e)\{

System.out.println("Helloword！！"+e);

return result;

public static String sendPost(String url,String param)

String result="";

try\{

URL httpurl = new URL(url);

HttpURLConnection httpConn = (HttpURLConnection)httpurl.openConnection();

httpConn.setDoOutput(true);

httpConn.setDoInput(true);

PrintWriter out = new PrintWriter(httpConn.getOutputStream());

out.print(param);

out.flush();

out.close();

BufferedReader in = new BufferedReader(new InputStreamReader(httpConn.getInputStream()));

String line;

while ((line = in.readLine())!= null)

result += line;

in.close();

\}catch(Exception e)\{

System.out.println("Helloword！"+e);

return result;

\`\`\`

下面给大家介绍 java得到GET和POST请求URL和参数列表的方法  在servlet中GET请求可以通过HttpServletRequest的getRequestURL方法和getQueryString()得到完整的请求路径和请求所有参数列表，POST的需要getParameterMap()方法遍历得到，不论GET或POST都可以通过getRequestURL+getParameterMap()来得到请求完整路径

\`\`\`java

package com.zuidaima

import java.io.IOException;

import java.io.PrintWriter;

import java.util.Map;

import javax.servlet.ServletException;

import javax.servlet.http.HttpServlet;

import javax.servlet.http.HttpServletRequest;

import javax.servlet.http.HttpServletResponse;

public class GetParams extends HttpServlet \{

private static final long serialVersionUID = 1L;

public GetParams() \{