Google Cloud Storage使用python批量上传文件

Bertha 。 2022-11-19 01:08 56阅读 0赞

假如我们有如下文件：

1.zip

2.zip

3.zip

4.zip

5.zip

6.zip

7.zip

8.zip

需要将其上传至gcs

简单的代码如下：

from google.cloud import storage
    
    
    ls=[]
    ls.append('1.zip')
    ls.append('2.zip')
    ls.append('3.zip')
    ls.append('4.zip')
    ls.append('5.zip')
    ls.append('6.zip')
    ls.append('7.zip')
    ls.append('8.zip')
    
    
    storage_client = storage.Client()
    bucket = storage_client.bucket('XXXX')
    for i in ls:
      blob = bucket.blob(i)
      blob.upload_from_filename(i)

但是想要更好的维护性，决定使用装饰器：

from google.cloud import storage
    
    storage_client = storage.Client()
    bucket = storage_client.bucket('XXXX')
    
    ls=[]  
    def ap(f):
        ls.append(f)
        return f
    
    @ap
    def _file1():
        blob = bucket.blob('1.zip')
        blob.upload_from_filename('1.zip')
        return 0
    @ap
    def _file2():
        blob = bucket.blob('2.zip')
        blob.upload_from_filename('2.zip')
        return 0   
       
    @ap
    def _file3():
        blob = bucket.blob('3.zip')
        blob.upload_from_filename('3.zip')
        return 0   
    
    @ap
    def _file4():
        blob = bucket.blob('4.zip')
        blob.upload_from_filename('4.zip')
        return 0
       
    @ap
    def _file5():
        blob = bucket.blob('5.zip')
        blob.upload_from_filename('5.zip')
        return 0
       
    @ap
    def _file6():
        blob = bucket.blob('6.zip')
        blob.upload_from_filename('6.zip')
        return 0   
       
    @ap
    def _file7():
        blob = bucket.blob('7.zip')
        blob.upload_from_filename('7.zip')
        return 0   
        
    @ap
    def _file8():
        blob = bucket.blob('8.zip')
        blob.upload_from_filename('8.zip')
        return 0   
       
    def upload():
        for f in ls:
            f() 
       
    upload()