python 实现列表嵌套字典去重、排序

蔚落 2022-12-22 09:25 259阅读 0赞

法一：注：根据字典的key去重

def delrepeat(data,key):  # data 列表  key 去重的键  
      new_data = [] # 用于存储去重后的list
      values = []  # 用于存储当前已有的值
      for d in data:
        if d[key] not in values:
          new_data.append(d)
          values.append(d[key])
      print(new_data)

if __name__ == '__main__': li = [{ 'ddate': '2020-11-11', 'likes': 257}, { 'ddate': '2020-11-18', 'likes': 257}, { 'ddate': '2020-11-15', 'likes': 257}, { 'ddate': '2020-11-15', 'likes': 256}]
        delrepeat(li, 'ddate')

效果图如下：  
![在这里插入图片描述][20201119112803862.png_pic_center]  
法二：注：根据字典去重 须列表有重复的字典

def remove_duplicate(dict_list): seen = set() new_dict_list = [] for dict in dict_list: t_dict = { 'ddate': dict['ddate'], 'likes': dict['likes']}
            t_tup = tuple(t_dict.items())
            if t_tup not in seen:
                seen.add(t_tup)
                new_dict_list.append(dict)
        print(new_dict_list)

效果图如下：  
![在这里插入图片描述][20201119113156221.png_pic_center]  
法三：须字典键值都是字符串

from functools import reduce def list_dict_duplicate_removal(): data_list = [{ "a": "123", "b": "321"}, { "a": "123", "b": "321"}, { "b": "321", "a": "123"}]
        run_function = lambda x, y: x if y in x else x + [y]
        return reduce(run_function, [[], ] + data_list)
    
    
    if __name__ == '__main__':
        print(list_dict_duplicate_removal())

效果图如下：  
![在这里插入图片描述][20201119113434564.png_pic_center]

列表嵌套字典排序如下：

li = [{ "ddate": "2020-11-11", "collects": 189}, { "ddate": "2020-11-18", "collects": 189}, { "ddate": "2020-11-15", "collects": 189}]
    new = sorted(li,key=lambda x:x["ddate"])
    print(new)

[20201119112803862.png_pic_center]: /images/20221120/64a9035bf6904731b5d30a92262a31b8.png
[20201119113156221.png_pic_center]: /images/20221120/7639ecebc1de43eea3a741a2f8ebabd8.png
[20201119113434564.png_pic_center]: /images/20221120/2c00c45d3d9d421f9c06fac8c15d16fa.png