[BUGKU][CTF][Reverse][2020] Reverse writeup 1-7 暂时肝不动了

不念不忘少年蓝@ 2023-01-06 05:45 76阅读 0赞

Reverse 入门逆向  
步骤: ida main函数 按R  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70]

Reverse signin  
关键字：  
知识点：Android逆向分析。（常用工具：安卓模拟器、JEB、Cyberchef、Androidkiller）  
步骤:  
1.用jeb打开，找到MainActivity，右键解析成java分析 ,需要反转后tostring()  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 1]  
2. 用jeb打开，找到MainActivity，右键解析成java分析  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 2]  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 3]  
3.[在线][Link 1]或者使用脚本反转 ,base64解码

a ='991YiZWOz81ZhFjZfJXdwk3X1k2XzIXZIt3ZhxmZ'
    
    b = ''
    
    b = a[::-1]
    
    print(b)

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 4]  
参考链接:https://www.cnblogs.com/myqzs/p/13724482.html

Reverse EASY re  
关键字：ida  
步骤:  
1.main f5 F5翻译为伪C代码  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 5]2.strcmp()对面输入的值是否等于xmmword\_413E34位置的值，双击xmmword\_413E34 跟过去，发现了flag （按R显示字符串）  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 6]3.字符串拼接后反转 ，得到flag  
DUTCTF\{We1c0met0DUTCTF\}

思路二：解压得到一个可执行文件，然后用Notepad++打开，直接搜索DUTCTF即可得到

Reverse Easy\_vb  
关键字：ida  
步骤:  
ida 打开 往下翻 MCTF 替换 flag  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 7]

Reverse Timer(阿里CTF)  
关键字：  
知识点：  
步骤:  
1.下载文件发现是apk ，先安装运行下发现有一个倒计时，只是时间为200000秒。猜测是让时间走完获取flag。

2.JEB查看

package net.bluelotus.tomorrow.easyandroid;
    
    import android.os.Bundle;
    import android.os.Handler;
    import android.support.v7.app.AppCompatActivity;
    import android.view.Menu;
    import android.view.MenuItem;
    import android.widget.TextView;
    
    public class MainActivity extends AppCompatActivity { 
        int beg = (((int) (System.currentTimeMillis() / 1000)) + 200000);
        int k = 0;
        int now;
        long t = 0;
    
        public native String stringFromJNI2(int i);
    
        public static boolean is2(int n) { 
            if (n <= 3) { 
                if (n > 1) { 
                    return true;
                }
                return false;
            } else if (n % 2 == 0 || n % 3 == 0) { 
                return false;
            } else { 
                int i = 5;
                while (i * i <= n) { 
                    if (n % i == 0 || n % (i + 2) == 0) { 
                        return false;
                    }
                    i += 6;
                }
                return true;
            }
        }
    
        protected void onCreate(Bundle savedInstanceState) { 
            super.onCreate(savedInstanceState);
            setContentView((int) R.layout.activity_main);
            final TextView tv1 = (TextView) findViewById(R.id.textView2);
            final TextView tv2 = (TextView) findViewById(R.id.textView3);
            final Handler handler = new Handler();
            handler.postDelayed(new Runnable() { 
                public void run() { 
                    MainActivity.this.t = System.currentTimeMillis();
                    MainActivity.this.now = (int) (MainActivity.this.t / 1000);
                    MainActivity.this.t = 1500 - (MainActivity.this.t % 1000);
                    tv2.setText("AliCTF");
                    if (MainActivity.this.beg - MainActivity.this.now <= 0) { 
                        tv1.setText("The flag is:");
                        tv2.setText("alictf{" + MainActivity.this.stringFromJNI2(MainActivity.this.k) + "}");
                    }
                    MainActivity mainActivity;
                    if (MainActivity.is2(MainActivity.this.beg - MainActivity.this.now)) { 
                        mainActivity = MainActivity.this;
                        mainActivity.k += 100;
                    } else { 
                        mainActivity = MainActivity.this;
                        mainActivity.k--;
                    }
                    tv1.setText("Time Remaining(s):" + (MainActivity.this.beg - MainActivity.this.now));
                    handler.postDelayed(this, MainActivity.this.t);
                }
            }, 0);
        }
    
        public boolean onCreateOptionsMenu(Menu menu) { 
            getMenuInflater().inflate(R.menu.menu_main, menu);
            return true;
        }
    
        public boolean onOptionsItemSelected(MenuItem item) { 
            if (item.getItemId() == R.id.action_settings) { 
                return true;
            }
            return super.onOptionsItemSelected(item);
        }
    
        static { 
            System.loadLibrary("lhm");
        }
    }

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 8]  
直接照着写一个即可，然后可以算出关键变量k  
解密脚本，算出k = 1616384

def is2(n):
        if(n <= 3):
            if(n > 1):
                return True
            return False
        elif(n % 2 == 0 or n % 3 == 0):
            return False
        else:
            i = 5
            while(i * i <= n):
                if (n % i == 0 or n % (i + 2) == 0):
                    return False
                i += 6
        return True
    
    k=0
    
    for i in  range(200000,0,-1):
        k = k + 100 if is2(i) else k - 1
    print(k)

![在这里插入图片描述][20210114153212851.png]3. 实现的话，用Androidkiller打开项目，因为跳转后输出了The flag is,所以搜索该字符串,双击跟过去

3.1 第113行的if-gtz v0, :cond\_0。 if-ltz是如果大于0跳转 ，那改成如果小于0跳转就跳过了200000秒等待了。对应的语句为if-ltz v0, :cond\_0。  
3.2 然后要找到赋值k的位置，看第129行-149行，因为k的值是在alictf\{和\}之间传入的。  
看到了139行的的iget v3, v3, Lnet/bluelotus/tomorrow/easyandroid/MainActivity;->k:I，知道v3是k的值。  
于是在下面赋值const v3,1616384

然后保存，编译，安装运行就出现flag。（jdk=1.8 apktool>=2.3）  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 9]

![在这里插入图片描述][20210114153101572.png]

![在这里插入图片描述][20210114153037857.png]

![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 10]

Reverse 逆向入门  
关键字：winhex  
步骤:

1.winhex 打开 复制黏贴到浏览器  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 11]2.QR扫描出结果  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 12]

Reverse 游戏过关  
关键字：ida  
步骤:  
1.首先就是看运行遍程序，了解下程序流程以及关键字符串。然后打开ida  
Shift+F12查看下字符串，然后双击过去  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 13]2.按Cirt+X交叉引用显示调用位置  
![在这里插入图片描述][watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L2RhZG9uZ3d1ZGk_size_16_color_FFFFFF_t_70 14]  
3.F5看下伪代码，两个数组按位异或再和0x13异或生成flag

array1 = [18,64,98,5,2,4,6,3,6,48,49,65,32,12,48,65,31,78,62,32,49,32,1,57,96,3,21,9,4,62,3,5,4,1,2,3,44,65,78,32,16,97,54,16,44,52,32,64,89,45,32,65,15,34,18,16,0]
    array2 = [123,32,18,98,119,108,65,41,124,80,125,38,124,111,74,49,83,108,94,108,84,6,96,83,44,121,104,110,32,95,117,101,99,123,127,119,96,48,107,71,92,29,81,107,90,85,64,12,43,76,86,13,114,1,117,126,0]
    
    flag = ''
    for i in range(len(array1)):
        flag+= chr(array1[i] ^ array2[i] ^ 0x13 )
    print(flag)

Reverse  
关键字：  
知识点：  
步骤:

参考链接：  
https://www.codeqq.com/log/7Zjb2O7Z.html

https://blog.csdn.net/ahilll/article/details/84787700

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[Link 1]: http://tool.huixiang360.com/str/reverse.php
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[20210114153101572.png]: /images/20221119/88dc1088aca2472daa44217732574fe9.png
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