天津理工大学密码学期末复习

喜欢ヅ旅行 2023-02-19 12:29 179阅读 0赞

## 1，单表与多表密码体制的概念是？ ##

单表密码体制：在一个密码体制中，如果明文字母对应的密文字母在密文中始终保持不变

多表密码体制：在一个密码体制中，如果明文中不同位置的同一明文字母在密文中对应的密文字母不同

## **2，密码体制中的5个有限集合，分组密码是什么？** ##

*  明文空间M
 *  密文空间C
 *  密钥空间K
 *  加密算法E
 *  解密算法D

**分组密码：**又称密钥密码，对称密码，它的加密密钥与解密密钥相同。利用分组密码对明文加密时首先对明文进行分组，每组长度相同，然后对每组明文分别加密得到等长密文。

## 3，Playfair密码体制的使用 ##

（由秘钥——》生成密钥矩阵——》按照加密规则得到密文）

内容介绍：

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 1][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 2][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 3][]

![20200620183242397.png][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 4][]

## 4，理解Vigenere密码体制 ##

Ci=(Mi+Ki)%26——》密文字母的下标=（明文字母的下标+秘钥字母的下标）%26

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 5][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 6][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 7][]

**例题解读：**

在表中找到第一个明文字母T的位置，和第一个密文字母c的位置，我们知道c的下标是2

（从0开始标记），所以字母T向后移动2个单位得到密文字母V。同理我们知道第二个密

文字母的i的下标是8，将明文字母h向后移动8个单位得到密文字母P

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## 5，Hill密码体制（如何进行加密，解密，证明其相关的题） ##

概念：

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 8][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 9][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 10][]

![20200620201023825.png][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 11][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 12][]

# #

## 6，仿射古典密码 ##

加密变换公式：C=(K1\*M+K2)mod26

解密变换公式：M=(K1逆)\*(C-K2)mod26

![20200620200929322.png][]

![20200620210532419.png][]

H——》（5\*7+7）%26=16——》Q

E——》（5\*4+7）%26=1——》B

L——》（5\*11+7）%26=10——》K

P——》（5\*15+7）%26=4——》E

M——》（5\*12+7）%26=15——》P

E——》（5\*4+7）%26=1——》B

代码实现：

package cn.itcast.util;
    
    import java.util.Scanner;
    
    public class communicate {
        public char []letters={'A','B','C','D','E','F','G','H','I','J','K','L','M',
                'N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
        public char []input=new char [20];
        public int getNum(char letter){
            for (int i=0;i<letters.length;i++){
                if (letter==letters[i])
                    return i;
            }
            return -1;
        }
        public static void main(String[] args) {
            communicate test=new communicate();
            Scanner input=new Scanner(System.in);
    
            while (true){
                System.out.println("请输入要加密的字符串");
                    int m1=test.getNum(input.next().charAt(0));
                    int c=(m1*5+7)%26;
                    System.out.println(test.letters[c]);
                }
    
            }
    
        }

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 13][]

# #

## 7，DES的基本加密步骤是什么？ ##

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 14][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 15][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 16][]

## 8，给DES的一个S盒的6bit输入数据，求出它的4bit输出数据 ##

如：输入101010，取出收尾的两位数字10做为行标2，中间的4位数字0101作为列标5，得到坐标（2,5）查下表得到结果6

——》0110作为输出数据

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 17][]

## 9，IDEA的基本加密过程是什么？ ##

## ![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 18][] ##

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 19][]

## 10，MA结构 ##

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 20][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 21][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 22][]

## 11，分组密码的两种结构是什么？ ##

*  Feistel网络

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 23][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 24][]

*  SP网络

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 25][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 26][]

\--------------------------------------------------------------------------------

## 12，公钥密码体制是什么？ ##

在公钥密码体制中，加密密钥和解密密钥是不一样的，加密密钥简称公钥，解密密钥简称私钥，加密密钥可以公开，解密密钥必须保密，从加密密钥计算解密密钥是难解的。

## 13，了解Merkle-Hellman背包算法（由明文求密文，由密文求明文） ##

## ![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 27][] ##

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 28][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 29][]

## 14，了解RSA公钥密码（中国剩余定理） ##

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 30][]

*  由题目中的p,q,e利用Euclid算法求解密钥d

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 31][]

*  由明文M，求密文C**（C=M的e次方modN）**

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 32][]

利用欧几里得算法计算解密密钥d=147

220=3\*73+1

3=1\*3+0

b    1      73

所以因为a是1奇数个，所以d=220-73=147

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 33][]

## 15，EIGamal公钥密码体制 ##

**证明其解密变换是加密变换的逆变换**

# #

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 34][]

16，证明：U属于Zn，并且U的逆对N的模运算是存在——》god(u,n)=1——》U属于Z\*n

P94,定理5.7的证明

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDg0MTMxMg_size_16_color_FFFFFF_t_70 35][]

## 17，了解Euler定理 ##

# #

![20200621143504659.png][]

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[20200620201023825.png]: https://img-blog.csdnimg.cn/20200620201023825.png
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[20200620200929322.png]: https://img-blog.csdnimg.cn/20200620200929322.png
[20200620210532419.png]: https://img-blog.csdnimg.cn/20200620210532419.png
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