Pygame添加自动对齐的按钮

ゞ浴缸里的玫瑰 2023-02-27 13:59 11阅读 0赞

Pygame真是原生态，连个按钮类都不给，那就只能自己写，对其坐标就行

先画一个长方形

BTH = 100
    BTY = 60
    pygame.draw.rect(window, (255, 0, 0), (100, 100, BTH, BTY), 0)

然后定义一个函数：

def button(name, bx, by, bw, bh):
        text1 = ft.render(name, True, (255, 255, 255))
        tw, th = text1.get_size()
        tx1 = bx + bw/2 - tw/2
        ty1 = by + bh/2 - th/2
        window.blit(text1, (tx1, ty1))
        pygame.display.update()

参数：显示文字，按钮X坐标起点、Y坐标起点、长和宽。

是用文字的get\_size()获取文字坐标，经过运算将其居中。即可。每次调用button(balabala)就行了。

实例代码：

import pygame
    WIN_WIDTH = 400
    WIN_HEIGHT = 600
    pygame.init()
    window = pygame.display.set_mode((WIN_WIDTH, WIN_HEIGHT))
    pygame.display.set_caption("Calc")
    titlelineico = pygame.image.load("img/airplane.ico")  # 导入窗口图标，规格：32x32，格式：.ico
    pygame.display.set_icon(titlelineico)  # 设置窗口图标
    window.fill((240, 240, 240))
    pygame.display.flip()
    ft = pygame.font.Font("Font/msyh.ttc", 25)
    
    def button(name, bx, by, bw, bh):
        text1 = ft.render(name, True, (255, 255, 255))
        tw, th = text1.get_size()
        tx1 = bx + bw/2 - tw/2
        ty1 = by + bh/2 - th/2
        window.blit(text1, (tx1, ty1))
        pygame.display.update()
    BTH = 100
    BTY = 60
    pygame.draw.rect(window, (255, 0, 0), (100, 100, BTH, BTY), 0)
    button("取消", 100, 100, BTH, BTY)
    pygame.display.update()
    while True:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                exit()

如果文字或者图形不会添加，可以看我的Pygame专栏前几个文章，都有详解