layui 日期框开始日期和结束日期不能超过当前时间并且开始时间不能超结束时间

素颜马尾好姑娘i 2023-02-28 11:17 1阅读 0赞

layui.use(['form', 'layedit', 'laydate'], function(){
            var form = layui.form
                ,layer = layui.layer
                ,layedit = layui.layedit
                ,laydate = layui.laydate;
    
            //日期
             var start_date =   laydate.render({
                elem: '#start_date'
                 ,format:'yyyy-MM-dd'
                 ,max : nowFormatDate()
                 ,done:function(value,date,startDate){
                     end_date.config.min = {
                         year: date.year,
                         month: date.month - 1,
                         date: date.date,
                         hours: date.hours,
                         minutes: date.minutes,
                         seconds: date.seconds
                     }
    
    
                 }
            });
            var   end_date = laydate.render({
                elem: '#end_date'
                ,format:'yyyy-MM-dd'
                ,max : nowFormatDate()
                ,done:function(value,date,startDate){
                    start_date.config.max = {
                        year: date.year,
                        month: date.month - 1,
                        date: date.date,
                        hours: date.hours,
                        minutes: date.minutes,
                        seconds: date.seconds
                    }
    
                }
            });
    
    
    
            function nowFormatDate() {
                var date = new Date(new Date()-1000*60*60*24);
                var seperator1 = "-";
                var seperator2 = ":";
                var month = date.getMonth() + 1;
                var strDate = date.getDate();
                if (month >= 1 && month <= 9) {
                    month = "0" + month;
                }
    
                if (strDate >= 0 && strDate <= 9) {
                    strDate = "0" + strDate;
                }
                var currentdate = date.getFullYear() + seperator1 + month
                    + seperator1 + strDate
                return currentdate;
            }
    
    
    
        });