PTA(Advanced Level) 1035：Password（C语言实现）-蒲公英云

PTA(Advanced Level) 1035：Password（C语言实现）

#include <stdio.h>
struct User
{ 
    char name[11],pass[11];
    int flag;//标记是否被修改过
}users[1000];
int isModify(char s[])
{ 
    int i,flag=0;
    for(i=0; s[i]; i++)
    { 
        if(s[i]=='0' || s[i]=='O' || s[i]=='1' || s[i]=='l')
        { 
            if(!flag)
                flag=1;
            if(s[i] == '0')
                s[i]='%';
            else if(s[i] == 'O')
                s[i]='o';
            else if(s[i] == '1')
                s[i]='@';
            else if(s[i] == 'l')
                s[i]='L';
        }
    }
    return flag;
}
int main()
{ 
    int m=0,n,i;
    char info[11]="";
    scanf("%d",&n);
    for(i=0; i<n; i++)
    { 
        users[i].flag=0;
        scanf("%s%s",users[i].name,users[i].pass);
        if(isModify(users[i].pass))
        { 
            m++;
            users[i].flag=1;//被修改过
        }
    }
    if(m==0)
    { 
        if(n > 1)
            printf("There are %d accounts and no account is modified",n);
        else
            printf("There is 1 account and no account is modified");
    }
    else
    { 
        printf("%d\n",m);
        for(i=0; i<n; i++)
            if(users[i].flag)
                printf("%s %s\n",users[i].name,users[i].pass);
    }
    return 0;
}