MySQL查询今天，昨天，近7天，本月…

╰+哭是因爲堅強的太久メ 2023-06-13 08:46 2阅读 0赞

**今天**  
select \* from 表名 where to\_days(时间字段名) = to\_days(now());

**昨天**  
SELECT \* FROM 表名 WHERE TO\_DAYS( NOW( ) ) - TO\_DAYS( 时间字段名) <= 1

**7天**  
SELECT \* FROM 表名 where DATE\_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

**近30天**  
SELECT \* FROM 表名 where DATE\_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

**本月**  
SELECT \* FROM 表名 WHERE DATE\_FORMAT( 时间字段名, '%Y%m' ) = DATE\_FORMAT( CURDATE( ) , '%Y%m' )

**上一月**  
SELECT \* FROM 表名 WHERE PERIOD\_DIFF( date\_format( now( ) , '%Y%m' ) , date\_format( 时间字段名, '%Y%m' ) ) =1

\#查询本季度数据  
select \* from \`ht\_invoice\_information\` where QUARTER(create\_date)=QUARTER(now());  
\#查询上季度数据  
select \* from \`ht\_invoice\_information\` where QUARTER(create\_date)=QUARTER(DATE\_SUB(now(),interval 1 QUARTER));  
\#查询本年数据  
select \* from \`ht\_invoice\_information\` where YEAR(create\_date)=YEAR(NOW());  
\#查询上年数据  
select \* from \`ht\_invoice\_information\` where year(create\_date)=year(date\_sub(now(),interval 1 year));

查询当前这周的数据   
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date\_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据  
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date\_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据  
select name,submittime from enterprise   where date\_format(submittime,'%Y-%m')=date\_format(now(),'%Y-%m')

查询距离当前现在6个月的数据  
select name,submittime from enterprise where submittime between date\_sub(now(),interval 6 month) and now();

查询上个月的数据  
select name,submittime from enterprise   where date\_format(submittime,'%Y-%m')=date\_format(DATE\_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select \* from \` user \` where DATE\_FORMAT(pudate, ' %Y%m ' ) = DATE\_FORMAT(CURDATE(), ' %Y%m ' ) ;

select \* from user where WEEKOFYEAR(FROM\_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select \*   
from user   
where MONTH (FROM\_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select \*   
from \[ user \]   
where YEAR (FROM\_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())  
and MONTH (FROM\_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select \*   
from \[ user \]   
where pudate between 上月最后一天  
and 下月第一天

where   date(regdate)   =   curdate();

select   \*   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())

SELECT date( c\_instime ) ,curdate( )  
FROM \`t\_score\`  
WHERE 1  
LIMIT 0 , 30