【Python】文本词频统计

我不是女神ヾ 2023-07-25 09:19 151阅读 0赞

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哈姆雷特英文

[https://python123.io/resources/pye/hamlet.txt][https_python123.io_resources_pye_hamlet.txt]

三国演义中文

[https://python123.io/resources/pye/threekingdoms.txt][https_python123.io_resources_pye_threekingdoms.txt]

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哈姆雷特英文词频分析

def getText():
        txt=open("hamlet.txt","r").read()#打开文本,输入具体的文本路径
        txt=txt.lower()#将文本中所有的英文字符变成小写
        for ch in '!"#$%&()*+,-./;:<=>?@[\\]^‘_{|}~':
            txt=txt.replace(ch," ")
        return txt #去掉特殊符号
    hamletTxt=getText()#调用函数对文本进行处理
    words=hamletTxt.split()#进行列表
    counts={}#字典
    for word in words:
        counts[word]=counts.get(word,0)+1#获取到的词在字典中寻找如果有的话在原来的基础上+1，如果没有就收录到字典中
    items=list(counts.items())#变成列表类型
    items.sort(key=lambda x:x[1],reverse=True)#对列表排序
    for i in range(10):#将出现次数前10的单词输出并输出出现次数
        word,count=items[i]
        print("{0:<10}{1:>5}".format(word,count))

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三国演义人物出场次数

import jieba#引入jieba分词库
    txt = open("threekingdoms.txt", "r", encoding="utf-8").read()#打开文本
    words = jieba.lcut(txt)#进行分词处理并形成列表
    counts = {}#构造字典，逐一遍历words中的中文单词进行处理，并用字典计数
    for word in words:
        if len(word) == 1:
            continue
        else:
            counts[word] = counts.get(word, 0) + 1
    items = list(counts.items())#转换列表类型并排序
    items.sort(key=lambda x:x[1], reverse=True)
    for i in range(15):#输出前15位单词
        word, count = items[i]
        print("{0:<10}{1:<5}".format(word, count))

结果：

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上面有不是人物的词，需要改造

import jieba
    txt = open("threekingdoms.txt", "r", encoding="utf-8").read()
    excludes = {
        "将军", "却说", "荆州", "二人", "不可", "不能", "如此", "主公",\
                "军士", "商议", "如何", "左右", "军马", "引兵", "次日", "大喜",\
                "天下", "东吴", "于是", "今日", "不敢", "魏兵", "陛下", "一人",\
                "都督", "人马", "不知"}#排除不是人名的词汇，加到这个排除词库中
    words = jieba.lcut(txt)
    counts = {}
    for word in words:#进行人名关联，防止重复
        if len(word) == 1:
            continue
        elif word == "诸葛亮" or word == "孔明曰":
            rword = "孔明"
        elif word == "关公" or word == "云长":
            rword = "关羽"
        elif word == "玄德" or word == "玄德曰":
            rword = "刘备"
        elif word == "孟德" or word == "丞相":
            rword = "曹操"
        else:
            rword = word
        counts[rword] = counts.get(rword, 0) + 1
    for word in excludes:
        del counts[word]
    items = list(counts.items())
    items.sort(key=lambda x:x[1], reverse=True)
    for i in range(10):
        word, count = items[i]
        print("{0:<10}{1:<5}".format(word, count))

结果

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不断优化。。。。

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[format_png]: /images/20230528/3db9d0b9cb2b4f8998cf367646a62e76.png
[https_python123.io_resources_pye_hamlet.txt]: https://python123.io/resources/pye/hamlet.txt
[https_python123.io_resources_pye_threekingdoms.txt]: https://python123.io/resources/pye/threekingdoms.txt
[format_png 1]: /images/20230528/488a4550809b4017914aa491a82ea3a4.png
[format_png 2]: /images/20230528/d9b4ab79997544fa9bf984b9b189fc09.png
[format_png 3]: /images/20230528/ee2186de51714621be32022b0e95552e.png
[format_png 4]: /images/20230528/96d4b69b32d1479f9fab5a9ae9447574.png
[format_png 5]: /images/20230528/37e030e56aed4957b54ca172ac4cb400.png
[format_png 6]: /images/20230528/d19750ccddee4d85929baa158a338067.png