c语言圣诞树代码

傷城~ 2023-09-23 20:15 92阅读 0赞

*C语言圣诞树*效果如下， 以下是程序的*源代码* 可直接复制在编译器打开运行(DEV C++)。

## **c语言圣诞树代码效果展示：** ##

![caad0a8a45c97069005bf2874a970f01.png][]

## **c语言圣诞树代码：** ##

#include <math.h>
    #include <stdio.h>
    #include <stdlib.h>
    #define PI 3.14159265359
    float sx, sy;
    float sdCircle(float px, float py, float r) {
    	float dx = px - sx, dy = py - sy;
    	return sqrtf(dx * dx + dy * dy) - r;
    }
    float opUnion(float d1, float d2) {
    	return d1 < d2 ? d1 : d2;
    }
    #define T px + scale * r* cosf(theta), py + scale * r * sin(theta)
    int ribbon() {
    	float x = (fmodf(sy, 0.1f) / 0.1f - 0.5f) * 0.5f;
    	return sx >= x - 0.05f && sx <= x + 0.05f;
    }
    float f(float px, float py, float theta, float scale, int n) {
    	float d = 0.0f;
    	for (float r = 0.0f; r < 0.8f; r += 0.02f)
    		d = opUnion(d, sdCircle(T, 0.05f * scale * (0.95f - r)));
    	if (n > 0)
    		for (int t = -1; t <= 1; t += 2) {
    			float tt = theta + t * 1.8f;
    			float ss = scale * 0.9f;
    			for (float r = 0.2f; r < 0.8f; r += 0.1f) {
    				d = opUnion(d, f(T, tt, ss * 0.5f, n - 1));
    				ss *= 0.8f;
    			}
    		}
    	return d;
    }
    int main(int argc, char* argv[]) {
    	int n = argc > 1 ? atoi(argv[1]) : 3;
    	float zoom = argc > 2 ? atof(argv[2]) : 1.0f;
    	for (sy = 0.8f; sy > 0.0f; sy -= 0.02f / zoom, putchar('\n'))
    		for (sx = -0.35f; sx < 0.35f; sx += 0.01f / zoom) {
    			if (f(0, 0, PI * 0.5f, 1.0f, n) < 0.0f) {
    				if (sy < 0.1f)
    					putchar('.');
    				else {
    					if (ribbon())
    						putchar('=');
    					else
    						putchar("...................................#j&o"[rand() % 32]);
    				}
    			}
    			else
    				putchar(' ');
    		}
    }
    //c语言圣诞树代码

[caad0a8a45c97069005bf2874a970f01.png]: https://img-blog.csdnimg.cn/img_convert/caad0a8a45c97069005bf2874a970f01.png